c++ - =* 是什么意思？（温索克 - C++）

Question

我正在了解 Winsock 并正在查看页面中的代码： Winsock 教程 1。

程序中有一行包含运算符 =*。谁能告诉我这是什么？我知道 a *= b 等价于 a = a * b。我在stackoverflow上读到=+是+=的过时形式。所以我尝试交换 * 和 = 使其成为 *=，但编译器给了我一个错误。如果有人告诉我这行代码的含义，我将不胜感激：

SockAddr.sin_addr.s_addr=*((unsigned long*)host->h_addr);

Answer 1

这意味着取消引用某些内容并将其分配给 LHS。

SomeType LHS;
SomeType* Something = ....;
LHS = *(Something);

请参阅取消引用运算符。

Answer 2

Operator =* existed in nascent versions of C language (as the original form of *= operator).

In C++ there's no such operator. =* is nothing else than = (assignment operator) followed by unary * (dereference operator). You can look up the meaning of = and unary * in your favorite C++ book.