mysql - Mysql按组计数发生

Question

嗨，我在 mysql DB 上有下表。

╔═══════════╦═════════╦════════╦════════════════╗
║ REVIEW_ID ║ USER_ID ║ STATUS ║   DATE_ADDED   ║
╠═══════════╬═════════╬════════╬════════════════╣
║       218 ║       2 ║ cool   ║ 20130121134811 ║
║       218 ║       2 ║ cool   ║ 20130121134812 ║
║       218 ║       2 ║ lame   ║ 20130121134813 ║
║       218 ║       2 ║ funny  ║ 20130121134814 ║
║       218 ║       2 ║ funny  ║ 20130121134815 ║
║       218 ║       2 ║ funny  ║ 20130121134816 ║
║       218 ║       2 ║ lame   ║ 20130121134817 ║
╚═══════════╩═════════╩════════╩════════════════╝

当我根据user_id需要获取每种类型的总状态结果进行查询时，如何获得结果：

╔════════╦════════════╗
║ STATUS ║ TOTALCOUNT ║
╠════════╬════════════╣
║ cool   ║          2 ║
║ funny  ║          3 ║
║ lame   ║          2 ║
╚════════╩════════════╝

谢谢

score 13 · Accepted Answer

使用COUNT()which 是一个聚合函数，并根据它们对它们进行分组status

SELECT  status, COUNT(*) totalCount
FROM    tableName
GROUP   BY status

SQLFiddle 演示

其他）

MySQL GROUP BY 和一些聚合函数列表

score 1 · Accepted Answer

1

SELECT status, count(*)
FROM your_table
GROUP BY status

于 2013-01-23T09:33:30.387 回答

score 1 · Accepted Answer

1

SELECT status, count(*)
FROM yourtable
GROUP BY status
;

于 2013-01-23T09:35:51.343 回答

score 0 · Accepted Answer

SELECT  STATUS, COUNT(*) AS TOTALCOUNT
FROM    tableName
GROUP   BY STATUS
HAVING   USER_ID = user_id you need

mysql - Mysql按组计数发生

4 回答 4

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