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我正在研究 SOAP 客户端。我的 WSDL URL 是http://localhost:8080/soap/getMessage?wsdl.

这需要以下标头来指定用户名和密码。

<wsdl:Envelope xmlns:soap="..."
        xmlns:wsse="..." >
       <wsdl:Header>
       <wsse:Security>
       <wsse:UsernameToken>
       <wsse:Username>admin</wsse:Username>
       <wsse:Password>password</wsse:Password>
       </wsse:UsernameToken>
       </wsse:Security>
       </wsdl:Header>
</wsdl:Envelope>

我必须为它编写一个程序。

有人能帮我吗。

谢谢。

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1 回答 1

2

这是我过去的肥皂程序。我已经根据您的情况对其进行了修改。

//create SOAP
        SOAPConnectionFactory sfc = SOAPConnectionFactory.newInstance();
        SOAPConnection connection = sfc.createConnection();

        SOAPMessage soapMessage = MessageFactory.newInstance().createMessage();
        SOAPPart soapPart = soapMessage.getSOAPPart();
        SOAPEnvelope soapEnvelope = soapPart.getEnvelope();

        SOAPBody soapBody = soapEnvelope.getBody();
        SOAPElement Header = soapBody.addBodyElement(new QName("Header"));

//attribute                     
        SOAPElement Security= Header.addChildElement(new QName("Security"));
        SOAPElement UsernameToken= Security.addChildElement(new QName("UsernameToken"));
        SOAPElement Username= UsernameToken.addChildElement(new QName("Username"));
        SOAPElement Password= UsernameToken.addChildElement(new QName("Password"));

//enter the username and password
Username.addTextNode("username");
Password.addTextNode("password");

//send the soap and print out the result
URL endpoint = "http://localhost:8080/soap/getMessage?wsdl";
        SOAPMessage response = connection.call(soapMessage, endpoint);


        ByteArrayOutputStream out = new ByteArrayOutputStream();
        String xml = "";
        try {
            response.writeTo(out);
            xml = out.toString("UTF-8");
        } catch (Exception e) 
        {
            System.out.println(""+e);
            //log.error(e.getMessage(),e);
        }         

System.out.println(""+xml);

有关更多信息,您可以搜索谷歌在 JDK 1.6 中使用 SOAP

于 2013-01-21T10:26:33.463 回答