我在处理 Utf8 时遇到问题。我已经将数据库和表更改为如下所示：
mysql>alter database database_name character set Utf8 collate utf8_unicode_ci;
mysql>alter table table_name character set Utf8 collate utf8_unicode_ci;
当我检查其变量以显示字符配置和排序规则配置时，它显示如下：
mysql> show variables like '%character%';
+--------------------------+----------------------------+
| Variable_name | Value |
+--------------------------+----------------------------+
| character_set_client | latin1 |
| character_set_connection | latin1 |
| character_set_database | utf8 |
| character_set_filesystem | binary |
| character_set_results | latin1 |
| character_set_server | latin1 |
| character_set_system | utf8 |
| character_sets_dir | /usr/share/mysql/charsets/ |
+--------------------------+----------------------------+
8 rows in set (0.00 sec)
mysql> show variables like '%collation%';
+----------------------+-------------------+
| Variable_name | Value |
+----------------------+-------------------+
| collation_connection | latin1_swedish_ci |
| collation_database | utf8_unicode_ci |
| collation_server | latin1_swedish_ci |
+----------------------+-------------------+
3 rows in set (0.00 sec)
当我将 /etc/my.cnf 设置为如下所示时，它运行良好：
[mysqld]
character-set-server=utf8
[mysql]
default-character-set=utf8
仅供参考，这是 JavaScript 上 Utf8 编码的代码：
var Utf8 = {
encode : function (string) {
string = string.replace(/\r\n/g,"\n");
var utftext = "";
deleteCookie('unicodeLength');
for (var n = 0; n < string.length; n++) {
var c = string.charCodeAt(n);
if (c < 128) {
utftext += String.fromCharCode(c);
}
else if((c > 127) && (c < 2048)) {
utftext += String.fromCharCode((c >> 6) | 192);
utftext += String.fromCharCode((c & 63) | 128);
}
else {
utftext += String.fromCharCode((c >> 12) | 224);
utftext += String.fromCharCode(((c >> 6) & 63) | 128);
utftext += String.fromCharCode((c & 63) | 128);
}
}
return utftext;
}
};
当这 2 行从 /etc/my.cnf 中删除时，问题就出现了。有什么建议么？