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可能重复:
从 unix 时间戳获取人类可读的相对时间和日期?

我所拥有的只是NSTimeInterval过去。如何将其转换为“ humanly readable”字符串,如“ 10 seconds ago”或“ 3 hours ago”?

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2 回答 2

2

NSTimeInterval 给你几秒钟。

确认秒数后,您可以使用 % 和 / 来查找天、小时、分钟和秒。

看这个演示:

NSInteger seconds = totalSecondsSinceStart % 60;
NSInteger minutes = (totalSecondsSinceStart / 60) % 60;
NSInteger hours = totalSecondsSinceStart / (60 * 60);
NSString *result = NSString stringWithFormat:@"%02ld hour %02ld minutues %02ld seconds ago", hours, minutes, seconds];

输出将如下所示:

01 hours 34 minutes 49 seconds ago
于 2013-01-16T13:04:27.593 回答
0

更多格式,因此您看不到 0 小时 0 分 34 秒。

+(NSString *)returnRelativeTime:(NSString *)dateString
{
    NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
    [formatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ssZ"];
    NSDate *date = [formatter dateFromString:dateString];
    int timeSince = [date timeIntervalSinceNow] * -1;

    int days    = (timeSince / (3600 * 24));
    int hours   = (timeSince / 3600)- (days *24);
    int minutes = (timeSince % 3600) / 60;
//    int seconds = (timeSince % 3600) %  60;
//    return [NSString stringWithFormat:@"%02d:%02d:%02d",hours ,minutes, seconds];
    if (days >0) {
         return [NSString stringWithFormat:@"%01d days %01d hours ago",days, hours];
    }
    else if (hours == 0) {
        return [NSString stringWithFormat:@"%01dm ago", minutes];
    }
    else {
        return [NSString stringWithFormat:@"%01dh %01dm ago", hours ,minutes];
    }

}
于 2013-01-16T13:58:14.717 回答