java - 当值超过 150 时，int 值不相等？

Question

代码看起来像

public void option() {
    seeTasks = tasks.getTasks();
        for (int i = 0; i < seeTasks.size(); i++) {
            for (int b = 0; b < seeBoxes.size(); b++) {
               System.out.println("see Tasks: " + seeTasks.get(i) + 
                           " see Boxes " + seeBoxes.get(b));
            if(seeTasks.get(i) == seeBoxes.get(b)) {
                option.add(seeTasks.get(i));
            }
        }
    }
    System.out.println(option);
}

如果的值 低于 150 ，则if语句seeTaks.get(i)不会通过。这怎么可能？seeTasks.get(i)如下所示，370 不包括在内。如果我将 110 更改为 150，它将无法通过。

println's 的输出是：

see Tasks: 50 see Boxes 50
see Tasks: 50 see Boxes 110
see Tasks: 50 see Boxes 150
see Tasks: 50 see Boxes 210
see Tasks: 50 see Boxes 270
see Tasks: 50 see Boxes 310
see Tasks: 50 see Boxes 370
see Tasks: 50 see Boxes 430
see Tasks: 110 see Boxes 50 
see Tasks: 110 see Boxes 110
see Tasks: 110 see Boxes 150
see Tasks: 110 see Boxes 210
see Tasks: 110 see Boxes 270
see Tasks: 110 see Boxes 310
see Tasks: 110 see Boxes 370
see Tasks: 110 see Boxes 430
see Tasks: 370 see Boxes 50
see Tasks: 370 see Boxes 110
see Tasks: 370 see Boxes 150
see Tasks: 370 see Boxes 210
see Tasks: 370 see Boxes 270
see Tasks: 370 see Boxes 310
see Tasks: 370 see Boxes 370
see Tasks: 370 see Boxes 430
[50, 110]

Answer 1

我猜测

seeTasks.get(i)

和

seeBoxes.get(b)

两者都返回一个Integer. 然后对于低于 128 的值，Integer缓存返回相同的实例，但对于较大的值，则返回新实例。使用equals().