我想制作一个应用程序，用户将在其中点击 QPushButton，这将触发辅助线程，该线程将向主窗口中的 QListWidget 添加一些文本。但是由于我无法弄清楚的原因，尽管从线程到主窗口的信号被发出，但它永远不会到达目的地。可能是因为连接失败。但是为什么会发生这种情况是我的代码（我的应用程序是使用 Visual Studio 2010 编译的）：
我的线程.h
#ifndef MY_THREAD_H
#define MY_THREAD_H
#include <QThread>
#include <QString>
class mythread:public QThread
{
Q_OBJECT
public:
void setName(QString& name);
signals:
void sendMsg(QString& msg);
protected:
void run();
private:
QString m_name;
QString msg;
};
#endif
我的线程.cpp
#include "mythread.h"
void mythread::setName(QString& name)
{
m_name=name;
}
void mythread::run()
{
msg="Hello "+m_name;
emit sendMsg(msg);
}
mydialog.h：
#ifndef MY_DIALOG_H
#define MY_DIALOG_H
#include <QtGui>
#include "mythread.h"
class mydialog:public QDialog
{
Q_OBJECT
public:
mydialog();
public slots:
void receiveMsg(QString& msg);
void fillList();
private:
QListWidget list1;
QPushButton btn1;
QGridLayout layout;
mythread thread;
};
#endif
mydialog.cpp：
#include "mydialog.h"
mydialog::mydialog()
{
layout.addWidget(&list1,0,0);
btn1.setText("Find");
layout.addWidget(&btn1,0,1);
setLayout(&layout);
QString myname="leonardo";
thread.setName(myname);
connect(&btn1,SIGNAL(clicked()),this,SLOT(fillList()));
connect(&thread,SIGNAL(sendMsg(QString&)),this,SLOT(receiveMsg(Qstring&)));
}
void mydialog::fillList()
{
thread.start();
}
void mydialog::receiveMsg(QString& msg)
{
list1.addItem(msg);
}
查找.cpp：
#include <QApplication>
#include "mydialog.h"
int main(int argc,char* argv[])
{
QApplication app(argc,argv);
mydialog window;
window.setWindowTitle("Find");
window.show();
return app.exec();
}
查找.pro：
TEMPLATE = app
TARGET =
DEPENDPATH += .
INCLUDEPATH += .
# Input
HEADERS += mydialog.h mythread.h
SOURCES += find.cpp mydialog.cpp mythread.cpp