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我遇到范围问题；我已经阅读了多个关于在 MySQL 中使用 OOP PHP 的 TUTS，但我仍然遇到问题.. 所以这里是：我有一个变量 ($GetUsersSQL)，其中包含 MySQL SELECT 用于检索用户数据以填充表。但是，当尝试对这些数据使用 MySQL UPDATE 时；它说 POST 数据为空。这就是我所拥有的（请原谅我在代码中的创可贴修复）。

Class Lib
{
        //public variables are still not retrieved by uploaddata method.
        public $rank;
        public $username;
        public $regiment;
        public $EventsRan;
        public $RankUp;
        public $DatePromoted;
        public $ReadNextRank;
        public $TimeReady;
        public $registered;
        public $ontag;
        public $Notes;
        public $GetUsersSQL;

    function Connection($host,$user,$password,$datab){
        $con = mysql_connect($host,$user,$password) or die(mysql_error());
            if (isset($con))
                {
                    $db = mysql_select_db($datab);
                }
        $LoginSQL = /**mysql_query("SELECT regiment FROM Users WHERE username='$username' AND password='$userpassword'")**/ mysql_query("SELECT * FROM NewOrder");

        $regiment = $LoginSQL;
    }
    function GetUsers($rank){
    $GetUsersSQL =/** mysql_query("SELECT * FROM Users WHERE regiment='$regiment' ORDER BY rank DESC")**/ mysql_query("SELECT * FROM NewOrder where rank='$rank'");
            while ($row = mysql_fetch_array($GetUsersSQL))
                {
                echo '
                    <tr>
                    <td>
                    <input  type="text" value="'.$row['Rank'].'" id="rank"></td>
                    <td><input  type="text" value="'.$row['Name'].'" id="name"></td>
                    <td><input type="text" value="'.$row['Regiment'].'" id="regiment"></td>
                    <td><input type="text" value="'.$row['Events Ran'].'" id="EventsRan"></td>
                    <td><input type="text" value="'.$row['Rank Up?'].'" id="RankUp"></td>
                    <td><input type="text" value="'.$row['Read next Rank'].'" id="ReadyNextRank"></td>
                    <td><input type="text" value="'.$row['Date Promoted'].'" id="DateLastPromoted"></td>
                    <td><input type="text" value="'.$row['Time ready'].'" id="TimeReady"></td>
                    <td><input type="text" value="'.$row['Registered'].'" id="Registered"></td>
                    <td><input type="text" value="'.$row['On Tag?'].'" id="OnTag"></td>
                    <td><input type="text" value="'.$row['Notes'].'" id="Notes"></td>
                ';
                }


        }
        public function __UploadData()
            {
                return $this->GetUsersSQL;
                //this is still broken
                if (isset($_POST['rank']))
                {
                    $this->rank = $_POST['rank'];
                    $this->name = $_POST['name'];
                    $this->regiment = $_POST['regiment'];
                    $this->EventsRan = $_POST['EventsRan'];
                    $this->RankUp = $_POST['RankUp'];
                    $this->DatePromoted = $_POST['DateLastPromoted'];
                    $this->ReadNextRank = $_POST['ReadyNextRank'];
                    $this->TimeReady = $_POST['TimeReady'];
                    $this->registered = $_POST['Registered'];
                    $this->ontag = $_POST['OnTag'];
                    $this->Notes = $_POST['Notes'];

                    $Query = mysql_query("UPDATE gfy SET rank='$this->rank', name='$this->name',ReadNextRank ='$this->ReadNextRank', regiment='$this->regiment', EventsRan='$this->EventsRan', RankUp='$this->RankUp', DatePromoted='$this->DatePromoted', timeReady='$this->Timeready',registered='$this->registered',ontag='$this->ontag' notes='$this->notes' WHERE name='$this->name'")or die(mysql_error());
                }
                else
                {
                    echo 'EMPTY';
                }

            }
}

自太平洋时间 2013 年 1 月 13 日凌晨 1:11 起进行了以下更改：致 GetUsers($rank): $this->GetUsersSQL = '...'; 到 _UploadData()： isset 更改为 isset($this->rank) 并且查询现在使用 '".$this->rank."'... vs '$rank'

4

1 回答 1

1

在你__UploadData()使用

public function __UploadData()
{
    return $this->GetUsersSQL; // execution is being terminated here
    $this->rank = $_POST['rank']; // out of reach
    $this->name = $_POST['name']; // out of reach
    // more code here
}

在这种情况下，因为return这里的关键字在return $this->GetUsersSQL进一步之前返回。同样在您的GetUsers()功能中

function GetUsers($rank){
    $GetUsersSQL = "...";
    // ...
}

你应该使用

$this->GetUsersSQL = "...";

同时替换以下行

mysql_query("UPDATE gfy SET rank='$this->rank', name='$this->name',ReadNextRank ='$this->ReadNextRank', regiment='$this->regiment', EventsRan='$this->EventsRan', RankUp='$this->RankUp', DatePromoted='$this->DatePromoted', timeReady='$this->Timeready',registered='$this->registered',ontag='$this->ontag' notes='$this->notes' WHERE name='$this->name'")or die(mysql_error());

和

mysql_query("UPDATE gfy SET rank='".$this->rank."', name='".$this->name."'...");
于 2013-01-13T07:47:58.720 回答