我想在 linux 内核中创建自己的 softirq。这样做是否正确:
在init
模块中,我想触发softirq
from 我将添加一个调用:
394 void open_softirq(int nr, void (*action)(struct softirq_action *))
395 {
396 softirq_vec[nr].action = action;
397 }
在片段中,我想提出 softirq,我将添加对raise_softirq
函数的调用:
379 void raise_softirq(unsigned int nr)
380 {
381 unsigned long flags;
382
383 local_irq_save(flags);
384 raise_softirq_irqoff(nr);
385 local_irq_restore(flags);
386 }
并添加我的新softirq
内容:
411 /* PLEASE, avoid to allocate new softirqs, if you need not _really_ high
412 frequency threaded job scheduling. For almost all the purposes
413 tasklets are more than enough. F.e. all serial device BHs et
414 al. should be converted to tasklets, not to softirqs.
415 */
416
417 enum
418 {
419 HI_SOFTIRQ=0,
420 TIMER_SOFTIRQ,
421 NET_TX_SOFTIRQ,
422 NET_RX_SOFTIRQ,
423 BLOCK_SOFTIRQ,
424 BLOCK_IOPOLL_SOFTIRQ,
425 TASKLET_SOFTIRQ,
426 SCHED_SOFTIRQ,
427 HRTIMER_SOFTIRQ,
428 RCU_SOFTIRQ, /* Preferable RCU should always be the last softirq */
429 MY_NEW_SOFTIRQ
430 NR_SOFTIRQS
431 };
在这里:
60 char *softirq_to_name[NR_SOFTIRQS] = {
61 "HI", "TIMER", "NET_TX", "NET_RX", "BLOCK", "BLOCK_IOPOLL",
62 "TASKLET", "SCHED", "HRTIMER", "RCU", "MY_NEW_SOFTIRQ"
63 };
问题:
- 我是对的还是我错过了什么?
- 这是正确的方法吗?还有其他选择吗?