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<?php

    $text=$_POST['text1'];

    $im1=$_POST['image'];

    echo $text;

    echo $im1;

    $im2 = new Imagick($im1);

    $im->annotateImage($im2, 0, 0, 0, $text);

    $im->setImageFormat('jpg');

    $thumbnail = $im->getImageBlob();

    header("Content-Type: $thumbnail");

    echo $thumbnail;

    echo '<img src="data:image/jpg;base64,'.base64_encode($thumbnail).'" />'; 
?>
4

1 回答 1

0

工作代码:

<?php
/* Create some objects */
$image = new Imagick();
$draw = new ImagickDraw();
$pixel = new ImagickPixel( 'gray' );

/* New image */
$image->newImage(800, 75, $pixel);

/* Black text */
$draw->setFillColor('black');

/* Font properties */
$draw->setFont('Bookman-DemiItalic');
$draw->setFontSize( 30 );

/* Create text */
$image->annotateImage($draw, 10, 45, 0, 'The quick brown fox jumps over the lazy dog');

/* Give image a format */
$image->setImageFormat('png');

/* Output the image with headers */
header('Content-type: image/png');
echo $image;

?>

如需进一步参考: http: //php.net/manual/en/imagick.annotateimage.php

于 2013-01-11T18:57:08.653 回答