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在以下字符串中如何删除所有特殊字符

str1="0Cell Phones: Smartphone,\x02\x05\x0e\x02\x05Mobile Phone - Best Buy13AT&T Wireless: AT&T Phones & Cell Phone Plans - Best Buy4\x02\x05\x0e\x02\x05Cell Phones: Smartphone, Mobile Phone - Best Buy1\x02\x05\x0e\x02\x05AT&T Wireless: AT&T Phones & Cell Phone Plans - Best Buy"
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1 回答 1

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使用ord()

In [35]: str1="0Cell Phones: Smartphone,\x02\x05\x0e\x02\x05Mobile Phone - Best Buy13AT&T Wireless: AT&T Phones & Cell Phone Plans - Best Buy4\x02\x05\x0e\x02\x05Cell Phones: Smartphone, Mobile Phone - Best Buy1\x02\x05\x0e\x02\x05AT&T Wireless: AT&T Phones & Cell Phone Plans - Best Buy"

In [36]: "".join(x for x in str1 if 31 < ord(x) <127)

Out[36]: '0Cell Phones: Smartphone,Mobile Phone - Best Buy13AT&T Wireless: AT&T Phones & Cell Phone Plans - Best Buy4Cell Phones: Smartphone, Mobile Phone - Best Buy1AT&T Wireless: AT&T Phones & Cell Phone Plans - Best Buy'

前 32 个是非打印字符,这个范围包括returnbackspace32-127是可打印的 ASCII 字符。

128-255: 扩展的 ASCII

ord()返回单个字符的整数值,我们可以通过31 < ord(x) <127.

在此处输入图像描述

于 2013-01-10T11:27:53.203 回答