java - Hibernate 和 PostgreSQL 中具有 UserType 的数组 --> MappingException

Question

我正在尝试编写一个实现 UserType 的类来处理 Hibernate/JPA 中的数组。我使用了以下帖子使用 hibernate和Hibernate/JPA/HSQL映射 postgres 数组：如何为用户类型 ARRAY 创建方言映射来构建解决方案，但我无法让它工作。我创建了一个新的 Spring Roo 项目只是为了测试它。以下是不同的文件（所有 java 类都位于包 test 中）：

持久性.xml

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
  <persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL">
    <provider>org.hibernate.ejb.HibernatePersistence</provider>
    <properties>
    <!--  <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect"/> -->
    <property name="hibernate.dialect" value="test.PostgreSQLDialectArray"/>
    <!-- value="create" to build a new database on each run; value="update" to modify an existing database; value="create-drop" means the same as "create" but also drops tables when Hibernate closes; value="validate" makes no changes to the database -->
    <property name="hibernate.hbm2ddl.auto" value="create"/>
    <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.ImprovedNamingStrategy"/>
    <property name="hibernate.connection.charSet" value="UTF-8"/>
    <!-- Uncomment the following two properties for JBoss only -->
    <!-- property name="hibernate.validator.apply_to_ddl" value="false" /-->
    <!-- property name="hibernate.validator.autoregister_listeners" value="false" /-->
    </properties>
  </persistence-unit>
</persistence>

TestArray.java

package test;

import java.math.BigInteger;
import java.security.SecureRandom;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.roo.addon.javabean.RooJavaBean;
import org.springframework.roo.addon.serializable.RooSerializable;
import org.springframework.roo.addon.tostring.RooToString;

@RooJavaBean
@RooToString
@RooSerializable
public class TestArray {


     private static final long serialVersionUID = 1L;
     private SecureRandom random = new SecureRandom();


     public String nextSessionId()
     {
         return new BigInteger(130, random).toString(32);
     }

     public static void main(String[] args) {
         ApplicationContext context;
 context = new ClassPathXmlApplicationContext("classpath:META-INF/spring/applicationContext.xml");
         int[] array = new int[1428];
         TestArray test = new TestArray();
         Blabla blabla = new Blabla();
         int nb = 1428;

         for(int i = 0 ; i < nb ; i++)
         array[i] = test.random.nextInt();

          //         blabla.setTest(array);
          //         blabla.persist();
          //        System.out.println(Arrays.toString(blabla.getTest()));

         System.out.println(java.sql.Types.ARRAY);
         System.out.println("Done");
     }
}

布拉布拉.java

package test;

import org.hibernate.annotations.Type;
import org.springframework.roo.addon.entity.RooEntity;
import org.springframework.roo.addon.javabean.RooJavaBean;
import org.springframework.roo.addon.tostring.RooToString;

@RooJavaBean
@RooToString
@RooEntity
public class Blabla {

    @Type(type = "test.IntArrayUserType")
    private int[] array;
}

PostgreSQL方言数组

package test;

import java.sql.Types;


public class PostgreSQLDialectArray extends org.hibernate.dialect.PostgreSQLDialect{

    public PostgreSQLDialectArray() { 
        super(); 
        registerHibernateType(Types.ARRAY, "array"); 
    }
 }

IntArrayUserType.java （基本上与使用 hibernate 映射 postgres 数组相同）

package test;
import java.io.Serializable;
import java.sql.Array;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;

import org.hibernate.HibernateException;
import org.hibernate.usertype.UserType;



public class IntArrayUserType implements UserType {

    protected static final int  SQLTYPE = java.sql.Types.ARRAY;

    private int[] toPrimitive(Integer[] array){
        int[] a = new int[array.length];
        for(int i = 0 ; i < array.length ; i++)
            a[i] = array[i];
        return a;
    }

    private Integer[] toObject(int[] array){
        Integer[] a = new Integer[array.length];
        for(int i = 0 ; i < array.length ; i++)
            a[i] = array[i];
        return a;
    }

    @Override
    public Object nullSafeGet(final ResultSet rs, final String[] names, final Object owner) throws HibernateException, SQLException {
        Array array = rs.getArray(names[0]);
        Integer[] javaArray = (Integer[]) array.getArray();
        return toPrimitive(javaArray);
    }

    @Override
    public void nullSafeSet(final PreparedStatement statement, final Object object, final int i) throws HibernateException, SQLException {
        System.out.println("test null safe set...");
        Connection connection = statement.getConnection();

        int[] castObject = (int[]) object;
        Integer[] integers = toObject(castObject);
        Array array = connection.createArrayOf("integer", integers);

        statement.setArray(i, array);
        System.out.println("test null safe set...");
    }

    @Override
    public Object assemble(final Serializable cached, final Object owner) throws HibernateException {
        return cached;
    }

    @Override
    public Object deepCopy(final Object o) throws HibernateException {
        return o == null ? null : ((int[]) o).clone();
    }

    @Override
    public Serializable disassemble(final Object o) throws HibernateException {
        return (Serializable) o;
    }

    @Override
    public boolean equals(final Object x, final Object y) throws HibernateException {
        return x == null ? y == null : x.equals(y);
    }

    @Override
    public int hashCode(final Object o) throws HibernateException {
        return o == null ? 0 : o.hashCode();
    }

    @Override
    public boolean isMutable() {
        return false;
    }

    @Override
    public Object replace(final Object original, final Object target, final Object owner) throws HibernateException {
        return original;
    }

    @Override
    public Class<int[]> returnedClass() {
        return int[].class;
    }

    @Override
    public int[] sqlTypes() {
        return new int[] { SQLTYPE };
    }
}

现在堆栈跟踪：

Exception in thread "main" org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'transactionManager' defined in class path resource [META-INF/spring/applicationContext.xml]: Cannot resolve reference to bean 'entityManagerFactory' while setting bean property 'entityManagerFactory'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [META-INF/spring/applicationContext.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: persistenceUnit] Unable to build EntityManagerFactory
at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:328)
at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:106)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1325)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1086)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:517)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:291)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:288)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:190)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:580)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:895)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:425)
at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139)
at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83)
at test.TestArray.main(TestArray.java:29)
Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [META-INF/spring/applicationContext.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: persistenceUnit] Unable to build EntityManagerFactory
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1420)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:291)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:288)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:190)
at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:322)
... 15 more
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: persistenceUnit] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:915)
at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:74)
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:225)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:308)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1477)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1417)
... 22 more
Caused by: org.hibernate.MappingException: No Dialect mapping for JDBC type: 2003
at org.hibernate.dialect.TypeNames.get(TypeNames.java:77)
at org.hibernate.dialect.TypeNames.get(TypeNames.java:100)
at org.hibernate.dialect.Dialect.getTypeName(Dialect.java:296)
at org.hibernate.mapping.Column.getSqlType(Column.java:208)
at org.hibernate.mapping.Table.sqlCreateString(Table.java:418)
at org.hibernate.cfg.Configuration.generateSchemaCreationScript(Configuration.java:1099)
at org.hibernate.tool.hbm2ddl.SchemaExport.<init>(SchemaExport.java:106)
at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:372)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1872)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:906)
... 27 more

所以我猜我创建的方言根本没有使用或者是错误的，但我不知道为什么。我认为 @Type 注释应该进行映射，但我已经看到了一些标签，但我不知道在这个例子中是否需要它们，如果它们是，我在哪里有它们？我被这个问题困扰已经两天了，我越来越绝望。你能帮我调试一下这个程序吗？请。非常感谢您提前。

编辑0：

persistence.xml 文件似乎找到了正确的方言，但函数 getTypeName(2003) 在执行 registerHibernateType(Types.ARRAY, "array") 后会引发上述错误。顺便说一句，我使用的是 Hibernate 3.6.4.Final 和 postgresql 8.4-702.jdbc3。

编辑1：

我将以下行添加到 PostgreSQLDialectArray 构造函数：

registerColumnType(Types.ARRAY, "integer[$l]" );

这似乎部分解决了问题。但是，现在我收到另一个错误：

2013-01-09 11:14:30,281 [main] ERROR org.hibernate.tool.hbm2ddl.SchemaExport - Unsuccessful: create table blabla (id int8 not null, array int[255], name varchar(255), test int4 not null, version int4, primary key (id))
2013-01-09 11:14:30,282 [main] ERROR org.hibernate.tool.hbm2ddl.SchemaExport - ERREUR: erreur de syntaxe sur ou près de « array »
  Position: 40

显然，hibernate 仍然不知道如何创建一个包含数组的表......

编辑2：

似乎 postgresql 不喜欢我的列被称为“数组”的事实。我改变了它，它起作用了。该表是由 hibernate 使用整数数组创建的。

但是由于 UserType 实现中的问题，我无法使用 hibernate 在其中保存任何数组。显然，数组的创建因 createArrayOf 而失败。我正在阅读有关此问题的一些线程，告诉访问底层连接而不是包装器。我想我要打开一个链接到这个的新线程，因为这个问题完全不同。

堆栈跟踪：

Exception in thread "main" java.lang.AbstractMethodError: org.apache.commons.dbcp.PoolingDataSource$PoolGuardConnectionWrapper.createArrayOf(Ljava/lang/String;[Ljava/lang/Object;)Ljava/sql/Array;
at test.IntArrayUserType.nullSafeSet(IntArrayUserType.java:59)
at org.hibernate.type.CustomType.nullSafeSet(CustomType.java:140)
at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2184)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2430)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2874)
at org.hibernate.action.EntityInsertAction.execute(EntityInsertAction.java:79)
at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:273)
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:265)
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:184)
at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:321)
at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:51)
at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1216)
at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:383)
at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:133)
at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:76)
at org.springframework.orm.jpa.JpaTransactionManager.doCommit(JpaTransactionManager.java:467)
at org.springframework.transaction.support.AbstractPlatformTransactionManager.processCommit(AbstractPlatformTransactionManager.java:754)
at org.springframework.transaction.support.AbstractPlatformTransactionManager.commit(AbstractPlatformTransactionManager.java:723)
at org.springframework.transaction.interceptor.TransactionAspectSupport.commitTransactionAfterReturning(TransactionAspectSupport.java:393)
at org.springframework.transaction.aspectj.AbstractTransactionAspect.ajc$afterReturning$org_springframework_transaction_aspectj_AbstractTransactionAspect$3$2a73e96c(AbstractTransactionAspect.aj:78)
at test.Blabla_Roo_Entity.ajc$interMethod$test_Blabla_Roo_Entity$test_Blabla$persist(Blabla_Roo_Entity.aj:56)
at test.Blabla.persist(Blabla.java:1)
at test.Blabla_Roo_Entity.ajc$interMethodDispatch1$test_Blabla_Roo_Entity$test_Blabla$persist(Blabla_Roo_Entity.aj)
at test.TestArray.main(TestArray.java:39)

编辑3：

最后，经过以下修改，整数数组的 UserType 可以工作了：

在 applicationContext.xml 中添加这一行：

<bean class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" id="dataSource">
....
<property name="accessToUnderlyingConnectionAllowed" value="true" />
</bean>

从 IntArrayUserType 修改 nullSafeSet

    @Override
    public void nullSafeSet(final PreparedStatement statement, final Object object, final int i) throws HibernateException, SQLException {
        Connection connection = statement.getConnection();
        int[] castObject = (int[]) object;
        Integer[] integers = toObject(castObject);
        Connection conn = ((DelegatingConnection) connection).getInnermostDelegate();
        Array array = conn.createArrayOf("integer", integers);
        statement.setArray(i, array);
    }

但是从 blabla 表中获取所有条目时仍然存在问题：函数 findAllBlablas 无法正常工作，只返回第一个条目...

编辑4：

事实上，它工作得很好，但 Eclipse 控制台无法打印所有数据。就这样！

score 2 · Accepted Answer

__________ HibernateSessionFactory.xml ___________________________

    <property name="hibernateProperties">
        <props>
            <!-- <prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop> -->
            <prop key="hibernate.dialect">com.test.model.PostgreSQLDialectArray</prop>              
            <prop key="hibernate.show_sql">true</prop>
            <prop key="hibernate.format_sql">true</prop>
            <prop key="hibernate.generate_statistics">false</prop>
            <prop key="hibernate.connection.pool_size">10</prop>
            <prop key="hibernate.archive.autodetection">class</prop>
            <prop key="hibernate.hbm2ddl.auto">create</prop>                
            <prop key="cache.provider_class">org.hibernate.cache.NoCacheProvider</prop>
        </props>
    </property>



    ______________ PostgreSQLDialectArray.java _______________________


package com.test.model;

import java.sql.Types;

public class PostgreSQLDialectArray extends org.hibernate.dialect.PostgreSQL82Dialect{

    public PostgreSQLDialectArray() {

        super();    

        System.out.println("Register Hibernate Type ... ");
        registerHibernateType(Types.ARRAY, "array");

        System.out.println("Register Column Type ... ");
        registerColumnType(Types.ARRAY, "integer[]");

    }
}



_____________ CustomArrayType.java ______________________________


package com.test.model;

import java.io.Serializable;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Types;
import java.sql.Array;

import org.hibernate.*;
import org.hibernate.engine.spi.SessionImplementor;
import org.hibernate.usertype.UserType;

 public class CustomArrayType implements UserType
 {

     protected static final int  SQLTYPE = java.sql.Types.ARRAY;

     private int[] toPrimitive(Integer[] array){
         int[] a = new int[array.length];
         for(int i = 0 ; i < array.length ; i++)
             a[i] = array[i];
         return a;
     }

     private Integer[] toObject(int[] array){
         Integer[] a = new Integer[array.length];
         for(int i = 0 ; i < array.length ; i++)
             a[i] = array[i];
         return a;
     }

     @Override
     public Object nullSafeGet(final ResultSet rs, final String[] names, SessionImplementor session, final Object owner) throws HibernateException, SQLException {
         Array array = rs.getArray(names[0]);
         Integer[] javaArray = (Integer[]) array.getArray();
         return toPrimitive(javaArray);
     }

     @Override
     public void nullSafeSet(final PreparedStatement statement, final Object object, final int i, SessionImplementor session) throws HibernateException, SQLException {
         System.out.println("test null safe set...");
         Connection connection = statement.getConnection();

         int[] castObject = (int[]) object;
         Integer[] integers = toObject(castObject);
         Array array = connection.createArrayOf("integer", integers);

         statement.setArray(i, array);
         System.out.println("test null safe set...");
     }

     @Override
     public Object assemble(final Serializable cached, final Object owner) throws HibernateException {
         return cached;
     }

     @Override
     public Object deepCopy(final Object o) throws HibernateException {
         return o == null ? null : ((int[]) o).clone();
     }

     @Override
     public Serializable disassemble(final Object o) throws HibernateException {
         return (Serializable) o;
     }

     @Override
     public boolean equals(final Object x, final Object y) throws HibernateException {
         return x == null ? y == null : x.equals(y);
     }

     @Override
     public int hashCode(final Object o) throws HibernateException {
         return o == null ? 0 : o.hashCode();
     }

     @Override
     public boolean isMutable() {
         return false;
     }

     @Override
     public Object replace(final Object original, final Object target, final Object owner) throws HibernateException {
         return original;
     }

     @Override
     public Class<int[]> returnedClass() {
         return int[].class;
     }

     @Override
     public int[] sqlTypes() {
         return new int[] { SQLTYPE };
     }

}



____________ MyClass.java ___________________________

package com.test.model;

import static javax.persistence.GenerationType.IDENTITY;

import java.io.Serializable;
import java.sql.Time;
import java.sql.Timestamp;
import java.sql.Types;
import java.util.Date;
import java.util.List;
import java.util.Set;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.EnumType;
import javax.persistence.Enumerated;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.JoinTable;
import javax.persistence.ManyToMany;
import javax.persistence.ManyToOne;
import javax.persistence.OneToMany;
import javax.persistence.Table;

import org.hibernate.annotations.Type;

@Entity
@Table(name = "MyClass")
public class MyClass implements Serializable {

    private static final long serialVersionUID = -2520209406925143850L;

    @Id
    @GeneratedValue(strategy = IDENTITY)
    private Long id;

    @Type(type = "com.test.model.CustomArrayType")
    @Column(name = "arrayDay", nullable = true)
    private int[] arrayDay;           

    public Long getId() {
    return id;
    }

    public void setId(Long id) {
    this.id = id;
    }

    public int[] getArrayDay() {
        return arrayDay;
    }

    public void setArrayDay(int[] arrayDay) {
        this.arrayDay = arrayDay;
    }  

}



______________ ArrayTypeTests.java ___________________________



package com.test;

import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.BeansException;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationContextAware;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;

import com.test.model.MyClass;
import com.test.service.MyClassService;

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = { "classpath:application-context.xml" })
public class ArrayTypeTests implements ApplicationContextAware {

    @Autowired
    private MyClassService myClassService;

    public static ApplicationContext ctx;

    @Test
    public void test_() {
       System.out.println("Test junit");
    }

    @Test
    public void test_arrayDays() {

    System.out.println("\n - Start test_array - ");
    MyClass myClass = myClassService.getMyClassById(1L);
    if (myClass != null) {
        int[] array = myClass.getArrayDay();
        System.out.println("\n valor1:" + array[0]);
        System.out.println("\n valor2:" + array[1]);
        System.out.println("\n\n test_array OK ");
    } else {
        System.out.println("\n ERROR");
    }
    System.out.println("\n - End test_array - ");

    }

    @Override
    public void setApplicationContext(ApplicationContext applicationContext) throws BeansException {
    ctx = applicationContext;
    }

}

score 1 · Accepted Answer

除了您在 Edit 3 中的解决方案之外，当您不使用 dbcp 或 c3p0 之类的连接池时，它可以完美运行。- 您正在使用 dbcp。

在使用 c3p0 时，一个可能的解决方案是使用proxool。有了这个，应该没有任何问题，因为 proxool 可以处理createArrayOf().

另一个是这样的：

    C3P0ProxyConnection connection = (C3P0ProxyConnection) _statement.getConnection();
    Method method = Connection.class.getMethod("createArrayOf", new Class[] { String.class, Object[].class });
    Array array = (Array) connection.rawConnectionOperation(
        method, C3P0ProxyConnection.RAW_CONNECTION, new Object[] {"integer", intArray});
    _statement.setArray(_i, array);

您需要从 jdbc-class 中获取底层函数。因此getMethod，将其与反射一起使用。

java - Hibernate 和 PostgreSQL 中具有 UserType 的数组 --> MappingException

2 回答 2

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