0

我正在开发一个小项目(C 编程)以通过代理进行隧道传输,当我尝试这样做时出现错误:

HTTP/1.0 400 Bad Request
Server: squid/2.7.STABLE9
Date: Mon, 07 Jan 2013 22:20:56 GMT
Content-Type: text/html 
Content-Length: 1456
X-Squid-Error: ERR_INVALID_REQ 0
X-Cache: MISS from xt03
Via: 1.0 xt03:80 (squid/2.7.STABLE9)
Connection: close

我发送到代理服务器的数据是:

 char msg[] = "CONNECT example.com:80 HTTP/1.0 <CR><LF> HOST example.com:80 <CR><LF> \n";

任何帮助都会很棒!

- - - 更新 - - -

我已经尝试了你们建议的方法,但我仍然遇到错误。我将发布我的整个代码集,看看它是否是套接字中的某些东西导致它发送错误的信息。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <sys/socket.h>
#include <sys/types.h>
#include <arpa/inet.h>
#include <netinet/in.h>

#define maxlen 2048

int main(int argc, char *argv[])
{
int mysocket;
int len;
char buffer[2000];
char msg[] = "CONNECT example.org:80 HTTP/1.0 \r\n HOST example.org:80 \r\n\r\n";


mysocket = socket(AF_INET, SOCK_STREAM, 0);

struct sockaddr_in dest;

memset(&dest, 0, sizeof(dest));

dest.sin_family = AF_INET;
dest.sin_addr.s_addr = inet_addr("125.39.66.150");
dest.sin_port = htons(80);

connect(mysocket, (struct sockaddr *)&dest, sizeof(struct sockaddr));

send(mysocket, msg, strlen(msg), 0);
len = recv(mysocket, buffer, maxlen, 0);

buffer[len] = '\0';

printf("%s \n", buffer);
close(mysocket);
return 0;

}

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新错误:

HTTP/1.0 400 Bad Request
Server: squid/2.7.STABLE5
Date: Tue, 08 Jan 2013 22:40:24 GMT
Content-Type: text/html
Content-Length: 1158
X-Squid-Error: ERR_INVALID_REQ 0
X-Cache: MISS from DXT-BJ-219
X-Cache-Lookup: NONE from DXT-BJ-219:80
Connection: close

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"         "http://www.w3.org/TR/html4/loose.dtd">
<HTML><HEAD><META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1">
<TITLE>ERROR: The requested URL could not be retrieved</TITLE>
<STYLE type="text/css"><!--BODY{background-color:#ffffff;font-family:verdana,sans-    serif}PRE{font-family:sans-serif}--></STYLE>
</HEAD><BODY>
<H1>ERROR</H1>
<H2>The requested URL could not be retrieved</H2>
<HR noshade size="1px">
<P> 
While trying to process the request:
<PRE>
CONNECT example.com:80 HTTP/1.1


</PRE>
<P>
The following error was encountered:
<UL>
<LI>
<STRONG>
Invalid Request
</STRONG>
</UL>

<P>
Some aspect of the HTTP Request is invalid.  Possible problems:
<UL>
<LI>Missing or unknown request method
<LI>Missing URL
<LI>Missing HTTP Identifier (HTTP/1.0)
<LI>Request is too large
<LI>Content-Length missing for POST or PUT requests
<LI>Illegal character in hostname; underscores are not allowed
</UL>
<P>Your cache administrator is <A HREF="mailto:noc_admin@163.com">noc_admin@163.com</A>. 

<BR clear="all">
<HR noshade size="1px">
<ADDRESS>
by DXT-BJ-219
</ADDRESS>
</BODY></HTML>
4

2 回答 2

3

“Bad request”是指您发送给服务器的请求格式不正确,无法被理解。我认为这样做的原因是您发送的是8个字符<CR><LF>(例如,'<'、'C'、'R' 等),而不是它们应该代表的 2 个字符,即\r\n.

尝试

char msg[] = "CONNECT example.com:80 HTTP/1.0\r\nHOST example:80\r\n\r\n";
于 2013-01-08T05:59:28.640 回答
0

参考这个:rfc2616

10.4.1 400 错误请求

由于语法错误,服务器无法理解该请求。客户端不应该在没有修改的情况下重复请求。

当你通过时:

char msg[] = "CONNECT example.com:80 HTTP/1.0 <CR><LF> HOST example.com:80 <CR><LF> \n";

然后,<CR><LF>部分可能会按原样作为字符串发送,而不是 ASCII 0xA 和 0xD,它们表示您打算发送的控制字符。最简单的解决方法是使用 C 等效项:\rfor<CR>\nfor <LF>

char msg[] = "CONNECT example.com:80 HTTP/1.0 \r\n HOST example.com:80 \r\n\r\n";

如果您打算扩展msg[]数组的使用以包含更多请求,您可能必须编写一个包装函数来将 CR、LF 和其他控制字符串msg[]转换为适当的 C 字符等效项以形成正确的消息。

希望这可以帮助。

于 2013-01-08T07:05:16.663 回答