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该应用程序与 PHP 类交互以从 MySQL 获取数据并使用 SQLite 在设备上存储用户数据，但它给了我错误消息。有人可以帮我解决吗？

数据库处理程序.java

public class DatabaseHandler extends SQLiteOpenHelper {

    // All Static variables
    // Database Version
    private static final int DATABASE_VERSION = 1;

    // Database Name
    private static final String DATABASE_NAME = "sqliteData";

    // Login table name
    private static final String TABLE_LOGIN = "login";

    // Login Table Columns names
    private static final String KEY_ID = "id";
    private static final String KEY_NAME = "name";
    private static final String KEY_ROLE = "role";

    public DatabaseHandler(Context context) {
        super(context, DATABASE_NAME, null, DATABASE_VERSION);
    }

    // Creating Tables
    @Override
    public void onCreate(SQLiteDatabase db) {
        String CREATE_LOGIN_TABLE = "CREATE TABLE " + TABLE_LOGIN + "("
                + KEY_ID + " INTEGER PRIMARY KEY," 
                + KEY_NAME + " TEXT," 
                + KEY_ROLE + " TEXT" + ")";

        db.execSQL(CREATE_LOGIN_TABLE);
    }

    // Upgrading database
    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        // Drop older table if existed
        db.execSQL("DROP TABLE IF EXISTS " + TABLE_LOGIN);

        // Create tables again
        onCreate(db);
    }

    /**
     * Storing user details in database
     * */
    public void addUser(String id, String name, String role) {
        SQLiteDatabase db = this.getWritableDatabase();

        ContentValues values = new ContentValues();
        values.put(KEY_ID, id); // id
        values.put(KEY_NAME, name); // Name
        values.put(KEY_ROLE, role); // Role

        // Inserting Row
        db.insert(TABLE_LOGIN, null, values);
        db.close(); // Closing database connection
    }

    /**
     * Getting user data from database
     * */
    public HashMap<String, String> getUserDetails(){
        HashMap<String,String> user = new HashMap<String,String>();
        String selectQuery = "SELECT  * FROM " + TABLE_LOGIN;

        SQLiteDatabase db = this.getReadableDatabase();
        Cursor cursor = db.rawQuery(selectQuery, null);
        // Move to first row
        cursor.moveToFirst();
        if(cursor.getCount() > 0){
            user.put("id", cursor.getString(1));
            user.put("name", cursor.getString(2));
            user.put("role", cursor.getString(3));
        }
        cursor.close();
        db.close();
        // return user
        return user;
    }

    /**
     * Getting user login status
     * return true if rows are there in table
     * */
    public int getRowCount() {
        String countQuery = "SELECT  * FROM " + TABLE_LOGIN;
        SQLiteDatabase db = this.getReadableDatabase();
        Cursor cursor = db.rawQuery(countQuery, null);
        int rowCount = cursor.getCount();
        db.close();
        cursor.close();

        // return row count
        return rowCount;
    }

    /**
     * Re crate database
     * Delete all tables and create them again
     * */
    public void resetTables(){
        SQLiteDatabase db = this.getWritableDatabase();
        // Delete All Rows
        db.delete(TABLE_LOGIN, null, null);
        db.close();
    }

}

日志猫

E/JSON(373): {"tag":"login","success":1,"error":0,"id":"013","user":{"name":"Mike Burton","role":"Developer"}}

I/Database(373): sqlite returned: error code = 1, msg = table login has no column named role

E/Database(373): Error inserting id=013 role=Developer name=Mike Burton

E/Database(373): android.database.sqlite.SQLiteException: table login has no column named role: , while compiling: INSERT INTO login(id, role, name) VALUES(?, ?, ?);
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1 回答 1

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听起来您可能已经修改了架构，但没有增加版本（因此数据库没有随着您的更改而重建）。如果是这种情况，您可以删除/重新安装您的应用程序或增加数据库版本以便onUpgrade调用。

于 2012-06-12T19:55:28.167 回答