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我正在开发一个 ios 应用程序,我需要在其中截取图像,但我无法在屏幕上截取正确的弹出框截图。这是我的实际图像

在此处输入图像描述

截屏后,我得到以下图像

在此处输入图像描述

我捕获图像的代码如下

    UIWindow *topWindow = nil;

    topWindow = [[[UIApplication sharedApplication] delegate] window];

    CGSize size = CGSizeZero;
    if(view == nil){
        size =  [[topWindow.rootViewController view] bounds].size;
    }else{
        size =  [view bounds].size;
    }

    if([UIScreen instancesRespondToSelector:@selector(scale)] && [[UIScreen mainScreen] scale] == 2.0f){
        UIGraphicsBeginImageContextWithOptions(size,NO,2.0f);
    }else{
        UIGraphicsBeginImageContext(size);
    }

    if(view == nil){
        // Put everything in the current view into the screenshot
        [[[[topWindow subviews] objectAtIndex:0] layer] renderInContext:UIGraphicsGetCurrentContext()];

        //Code for capturing popover
        [[[topWindow subviews].lastObject layer] renderInContext:UIGraphicsGetCurrentContext()];

        }
    }else{
        // Put everything in the current view into the screenshot
        [[view layer] renderInContext:UIGraphicsGetCurrentContext()];
    }

    // Save the current image context info into a UIImage
    UIImage *imageToBeEdited = UIGraphicsGetImageFromCurrentImageContext();
    UIGraphicsEndImageContext();
4

1 回答 1

0

请尝试更改:

if(view == nil)
{
   size =  [[topWindow.rootViewController view] bounds].size;
}else{
   size =  [view bounds].size;
}

至 :

if(view == nil)
{
    size =  [[topWindow.rootViewController view] bounds].size;
}else{
    size =  view.frame.size;
}
于 2013-01-07T12:27:39.887 回答