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我在 android 中使用 GCM,我通过 asp.net 服务器将数据发送到设备,如下代码所示。

public void SendCommandToPhone(String sCommand)
    {
        String DeviceID = "";
        DeviceID = "APA91bF9SSDEp-UPU8UwvctGt5ogfrSw0UdilTWlCujqItHcr-eiPJ31ZDI-IeqTbLr92ZOPF31bXtB1_5gNEPHAq82N4ji0stm4cy9U0Yuk0Awhjl9PS02okuc9rRhJobkgOt-ofm5Br0KR-Y";
        WebRequest tRequest;
        tRequest = WebRequest.Create("https://android.googleapis.com/gcm/send");
        tRequest.Method = "post";
        //tRequest.ContentType = "application/json";
        tRequest.ContentType = "application/x-www-form-urlencoded";
        tRequest.Headers.Add(string.Format("Authorization: key={0}", "AIzaSyBgCKDhyHnRmmu8jCfmupHVJA8cVkIa-XEZS"));
        String collaspeKey = Guid.NewGuid().ToString("n");
        String postData = string.Format("registration_id={0}&data.message={1}&collapse_key={2}", DeviceID, "YourMessage", collaspeKey);
        Byte[] byteArray = Encoding.UTF8.GetBytes(postData);
        tRequest.ContentLength = byteArray.Length;
        Stream dataStream = tRequest.GetRequestStream();
        dataStream.Write(byteArray, 0, byteArray.Length);
        dataStream.Close();
        WebResponse tResponse = tRequest.GetResponse();
        dataStream = tResponse.GetResponseStream();
        StreamReader tReader = new StreamReader(dataStream);
        String sResponseFromServer = tReader.ReadToEnd();
        tReader.Close();
        dataStream.Close();
        tResponse.Close();
    }

并在应用程序 onMessage 代码如下

@Override
protected void onMessage(Context context, Intent intent) {
String message = intent.getStringExtra("message");
}

当我调用 asp.net 服务时,它在调试中正确调用,但这里的消息字符串为空。

任何人都可以帮忙,我哪里出错了......

4

3 回答 3

1

您的消息应使用以下参数发布:

'registration_ids' => DeviceID ,
'data' => array( "notification" => YOUR_JSON_MESSAGE_STRING),

在安卓端,:

Bundle data = intent.getExtras();
data.getString("notification")
于 2013-01-02T10:43:37.050 回答
0

在应用程序中试试这个

@Override
protected void onMessage(Context context, Intent intent) {
Bundle extras = intent.getExtras();
String message = extras.getString("message");
}
于 2013-01-02T10:08:27.827 回答
0

可能的原因是提供给参数的“消息”与服务器中定义的内容不完全相同。

您的代码:

@Override
protected void onMessage(Context context, Intent intent) {
     String message = intent.getStringExtra("message");
}

但在服务器中,例如 PHP 服务器:

$msg = array("mess" => "Hellow World!");
sendNotif($msg);

在 PHP 文件中查看 mess!= 消息,除非您将代码更改为

 @Override  
 protected void onMessage(Context context, Intent intent) {
      String message = intent.getStringExtra("mess");
 }
于 2014-12-13T07:50:21.277 回答