嘿,所以我试图通过 AJAX 调用将数据放入这个 div
<div class="scroll-pane2 blue small" style="">
<p id="bulletinBodyArea" style="margin-right:20px;"></p>
</div>
当单击从数据库提供的链接之一时,将触发 AJAX
<div class="bulletinSectionAccordion rounded">
<p class="blue" style="font-size:19px;margin-left:23px;margin-top:15px;margin-bottom:10px;">Archives</p>
<?php
$query = "SELECT * FROM `bulletin` LEFT JOIN `bulletininschool` ON `bulletin`.`id`=`bulletininschool`.`bulletin` WHERE `school` = 2 ";
$result=$connection->query($query);
while($row = $result->fetch_array()) {
echo '<p class="medium titi" style="margin-left:23px;">'.$row['title'].'</p>';
}
?>
</div>
它被调用然后传递数据
$(".titi").click(
getBody
);
function getBody(){
$("#bulletinBodyArea").load('update/getBody.php');
};
这是 AJAX 功能
<?php
$section='bulletin';
$table="bulletin";
$schoolSelectorTable="bulletininschool";
$schoolSelector="bulletin";
$db_host = "localhost";
$db_user = "root";
$db_pass = "";
$db_name = "isl";
mysql_connect($db_host, $db_user, $db_pass, $db_name);
mysql_select_db("isl") or die(mysql_error());
$states = mysql_query("SELECT * FROM `bulletin` LEFT JOIN `bulletininschool` ON `bulletin`.`id`=`bulletininschool`.`bulletin` WHERE `school` = 2" );
while($state = mysql_fetch_array($states)){
echo "<p>".$state['body']."</p>";
}
?>
现在,从数据库提供的单击链接实际上是文章标题,然后当单击特定标题时,AJAX 调用应该去获取与该文章关联的正文文本。但我无法理解我应该如何度过难关。我正在做正确的查询并获取标题和正文,但我无法弄清楚如何将它们关联起来。我是否将变量传递给 AJAX 调用?
谢谢