6

我正在尝试执行以下操作:一旦我的 listview IsSelected,我想将我的按钮IsEnabled属性设置为 true。

这是我尝试过的,但出现以下异常:

'Initialization of 'System.Windows.Controls.ListView' threw an exception.' Line number '25' and line position '19'.

这是代码:

 <ListView ItemsSource="{Binding ReferenceCollection}" SelectedItem="{Binding SelectedReference}" Grid.ColumnSpan="2" Name="ListView1"  >
        <ListView.Triggers>
            <Trigger Property="ListView.IsSelected" Value="True">
                <Setter TargetName="okBtn" Property="Button.IsEnabled" Value="True" />
            </Trigger>
        </ListView.Triggers>
        <ListView.ItemTemplate>
            <DataTemplate>
                <StackPanel Orientation="Horizontal">
                    <Label Content="{Binding ReferenceName}" />
                </StackPanel>
            </DataTemplate>
        </ListView.ItemTemplate>
    </ListView>

和按钮:

 <Button IsEnabled ="False" Grid.Row ="2" Content="OK" Name="okBtn" Click="addReference_Click" />
4

1 回答 1

4

您可以在按钮中使用 DataTrigger:

<ListView Name="YourList">
        <ListViewItem Content="1234" />
        <ListViewItem Content="1234" />
        <ListViewItem Content="1234" />
    </ListView>
    <Button Content="OK">
        <Button.Style>
            <Style TargetType="{x:Type Button}">
                <Style.Triggers>
                    <DataTrigger Binding="{Binding SelectedItem, ElementName=YourList}"
                                 Value="{x:Null}">
                        <Setter Property="IsEnabled"
                                Value="False" />
                    </DataTrigger>
                </Style.Triggers>
            </Style>
        </Button.Style>
    </Button>
于 2012-12-25T07:19:43.233 回答