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我继承了我必须维护的 Symfony 1.4/Doctrine 1.2 应用程序。我正在尝试对 schema.yml 文件进行一些更改并从中生成新模型和 sql defns,但由于某种原因,我的外键关系没有完全生成。

我认为我可能在 schema.yml 文件中遗漏了一些明显的东西,但它并没有出现在我身上:

我已将 schema.yml 文件编辑为一些基础知识:

SCHEMA.YML:
connection: doctrine
options:
  type: innodb
  charset: utf8

MasterIndex:
  tableName: master_index
  columns:
    id:
      type: integer
      primary: true
      autoincrement: true
    last_name:
      type: string(255)
      notnull: true
    first_name:
      type: string(255)
      notnull: true

Poem:
  tableName: poem
  columns:
    id:
      type: integer
      primary: true
      autoincrement: true
    user_id: string(50)
    title: string(250)
    pen_name: string(250)
    contents: string()
    invoice_id: integer
  relations:
    Invoice:
      local: invoice_id
      foreign: id
      foreignAlias: poems
      foreignType: many
      type: one
    MasterIndex:
      local: user_id
      foreign: id
      foreignAlias: poems
      foreignType: one
      type: many

Invoice:
  tableName: invoice
  columns:
    id:
      type: integer
      primary: true
      autoincrement: true
    user_id:
      type: string(50)
      notnull: true
    amount:
      type: float()
      notnull: true

运行 symfony 学说:清洁学说:构建模型和学说:构建 sql 后,我得到以下 schema.sql 生成:

CREATE TABLE invoice (id BIGINT AUTO_INCREMENT, user_id VARCHAR(50) NOT NULL, amount FLOAT(18, 2) NOT NULL, PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 ENGINE = innodb;
CREATE TABLE master_index (id BIGINT AUTO_INCREMENT, last_name VARCHAR(255) NOT NULL, first_name VARCHAR(255) NOT NULL, PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 ENGINE = innodb;
CREATE TABLE poem (id BIGINT AUTO_INCREMENT, user_id VARCHAR(50), title VARCHAR(250), pen_name VARCHAR(250), contents TEXT, invoice_id BIGINT, INDEX invoice_id_idx (invoice_id), PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 ENGINE = innodb;
ALTER TABLE poem ADD CONSTRAINT poem_invoice_id_invoice_id FOREIGN KEY (invoice_id) REFERENCES invoice(id);

我期待诗表中有 2 个外键约束 - invoice_id 到 Invoice 表,user_id 到 MasterIndex 表,但只出现一个约束!我在 master_index 表的诗歌表中缺少我的外键约束。

我是否忽略了一些明显的东西?

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1 回答 1

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外键必须与引用列的类型匹配:

user_id: type: string(50)应该是user_id: type: integer

于 2012-12-21T12:17:42.367 回答