3

我在 php 方面不是那么好，所以我很感激你的帮助。

我需要将某些数据从一个 mysql 表更新或插入到同一台服务器的另一个 mysql 表！

购买的表具有相同的列，我想要的是用预先选择的中间值更新某些行！桌子：

|ID| |mid| |value1| |value2|

我做了 php for update 或 insert 检查它是否存在的部分，但我需要它做的是重复每个给定的步骤 pos

所以我需要它来为我列出的每个中间重复这个脚本来完成

mid1 = 66
mid2 = 78
mid3 = 24


$con = mysql_connect("localhost","User","Pass");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db(baza, $con);

$result = mysql_query("SELECT * FROM table WHERE mid='???' ");

while($row = mysql_fetch_array($result))
{
$mid=$row['mid'];
$name=$row['value1'];
$alias=$row['value2'];
}

mysql_close($con);
?> 
<?php
$con2 = mysql_connect("localhost","user2","pass2");
if (!$con2)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db(baza2, $con2);


$query = "SELECT * FROM table WHERE mid='$mid' ";
$resulta = mysql_query($query) or die(mysql_error());

if (mysql_num_rows($resulta) )
{

mysql_query("UPDATE table SET mid='$mid', name='$name', alias='$alias'");
mysql_close($con2);
echo "1 record added1";
}
else
{
$sql="INSERT INTO table (mid, name, alias)
VALUES
('$mid','$name','$alias')";

if (!mysql_query($sql,$con2))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($con2);
}

先感谢您！

4

1 回答 1

1

如果 2 个数据库在同一台服务器上，您可以设置您的帐户以访问这两个数据库。如果是这样，您可以通过这种方式在查询中简单地选择数据库：

mysql_query("SELECT * FROM my_database.my_table WHERE ..");

你的代码将是..

$mid_array = array(66, 78, 24);
$con = mysql_connect("localhost","user","pass");
if(!$con) {
    die('could not connect: '.mysql_error());
}
mysql_select_db(baza, $con);

foreach($mid_array AS $mid) {
    $result = mysql_query("SELECT * FROM table WHERE mid = '".$mid."'";
    while($row = mysql_fetch_array($result)) {
       mysql_query("INSERT INTO baza2.table (mid, name, alias) VALUES ('".$row['mid']."', '".$row['name']."', '".$row['alias']."') ON DUPLICATE KEY UPDATE name = '".$row['name']."', alias = '".$row['alias']."'");
    }
}
mysql_close($con);

You don't need a different query to check if the record with mid = .. already exists. You can simply handle this with the mysql ON DUPLICATE KEY UPDATE statement which will do this for you in only 1 query!

于 2012-12-19T12:11:40.237 回答