linux - sh script escaping

Question

From a linux terminal the command:

 ls application/js/{a*,b*,c*,d*,e.pocket-secure}

Will list all files in the application/js directory that start with a,b,c,d or e.pocket-secure.

If I place that command in doit.sh and execute:

sh doit.sh

I get:

ls: cannot access application/js/{a*,b*,c*,d*,e.pocket-secure*}: No such file or directory

I think the {} is confusing the shell interpreter, but I tried quoting (single|double) and also tried escaping the {} to no avail.

Answer 1

当您在终端中键入时，我怀疑您在bash. 当你运行时sh doit.sh，你正在改变 shell 的特性，要么是因为bash处于兼容模式，要么是因为你正在使用类似dash. 尝试做bash doit.sh。

Answer 2

这种语法只适用于 bash 解释器你可以试试这个

#/bin/bash
ls application/js/{a*,b*,c*,d*,e.pocket-secure}

和

chmod +x doit.sh
./doit.sh

或者

只需在 shell 上输入

bash doit.sh