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在阅读了很多问题和答案后，我决定使用 MultipartEntity。这个答案一定是最好的： https ://stackoverflow.com/a/2937140/1388723

我已经实现了它：

private class SendImage extends AsyncTask<String, Void, Void> {
    String sresponse;

    @Override
    protected Void doInBackground(String... params) {
        HttpClient httpClient = new DefaultHttpClient();
        HttpContext localContext = new BasicHttpContext();
        HttpPost httpPost = new HttpPost(
                "http://taras.xin.com.pl/loadimage.php");
        InputStream in = null;
        try {
            MultipartEntity entity = new MultipartEntity(
                    HttpMultipartMode.BROWSER_COMPATIBLE);
            Log.i("MultyPart", params[0]);
            File file = new File(params[0]);
            Log.i("MultyPartFILE", file.toString());
            ContentBody fb = new FileBody(file, "image/jpeg");
            Log.i("MultyPartFB", fb.toString());
            entity.addPart("text", new StringBody(
                    "This text was added to posrt"));
            entity.addPart("word", new StringBody(
                    "This text was added to post"));
            entity.addPart("file", fb);
            httpPost.setEntity(entity);
            HttpResponse response = httpClient.execute(httpPost,
                    localContext);
            in = response.getEntity().getContent();
        } catch (IOException e) {
            e.printStackTrace();
        }

        try {
            BufferedReader reader = new BufferedReader(
                    new InputStreamReader(in, "UTF-8"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            in.close();
            sresponse = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

        return null;
    }

    @Override
    protected void onPostExecute(Void result) {

        runOnUiThread(new Runnable() {

            @Override
            public void run() {
                text.setText(sresponse);
            }
        });

        super.onPostExecute(result);
    }
}

和我的 loadimage.php：

    <?php
     var_dump($_POST);
     var_dump($_FILE);
      ?>

我收到两个 $_POST 字符串，但 FileBody(file) 甚至没有影子。$_FILE 给出空值。

确切地说，我已经下载了 httpcomponents-client-4.2.2-bin，提取了 httpmime-4.2.2.jar。

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1 回答 1

0

尝试仅获取您发送的
文件 $file = $_FILES['file'];

于 2013-02-20T19:08:40.510 回答