iphone - 将字符串与 xcode 中的 NSMutablearray 数据进行比较？

Question

我有一个 NSMutableArray，我需要将其中的内容与 NSString 进行比较。但无法得到它？

我的阵列

(
{
  Code=Sunday;
},
{
 Code=Monday;
},
{
Code=Tuesday;
}
)

我是这样比较的：

BOOL isTheObjectThere = [array containsObject:weekday];

if([arr count]==0 && isTheObjectThere==YES)
{
//do something
}
else
{
//do something
}

这里 weekday 是 NSString ，其 value=Sunday

但是 isTheObjectThere 正在返回 NO..

我哪里错了？

Answer 1

看这个例子

NSMutableArray* array = [NSArray arrayWithObjects:@"Sunday", @"Monday", @"Tuesday", nil];

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF IN %@", array];
BOOL isTheObjectThere = [predicate evaluateWithObject:@"Sunday"];
NSLog(@"isTheObjectThere %d",isTheObjectThere);

它的工作正常并返回是TheObjectThere 1

Answer 2

该数组包含字典元素，然后检索键（代码）的值。

 NSMutableArray *yourArray = [[NSMutableArray alloc] init];
    for (NSDictionary *dict in array) {
        [yourArray addObject:[dict valueForKey:@"Code"]];
    }
    BOOL isTheObjectThere = [yourArray containsObject:@"Sunday"];

Answer 3

BOOL isTheObjectThere = [array containsObject:weekday];

不行，最好试试下面的方法。

    NSMutableArray* inputArray = [NSArray arrayWithObjects:@"Sunday", @"Monday", @"Tuesday", nil];

for (NSString* item in inputArray)
{



if ([item rangeOfString:@"Sunday"].location != NSNotFound)


{
   //do something
  }



else


{
  //do something;
 } 

}

Answer 4

NSString *yourString = @"Monday";

for (NSString* item in inputArray){
if ([yourString rangeOfString:item].location != NSNotFound)
//Do something;

else
// Do the other Thing;
}