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您好，我正在尝试成功选择行作为 mysql 中的列。

也许有人可以帮助我。

这就是我的桌子的样子

+----------+----------------------------------------------------+----------+
| brand_id | brand_name                                         | linecode | 
+----------+----------------------------------------------------+----------+
| DPQT     | 1-800 Tow Truck                                    | DER      | 
| DPQT     | 1-800 Tow Truck                                    | DCF      |
| DPQT     | 1-800 Tow Truck                                    | DCA      |
| DPQT     | 1-800 Tow Truck                                    | AAA      |
| DPQT     | 1-800 Tow Truck                                    | DDD      |
| BLGR     | 1-800-Radiator                                     | Curt     |
| BGVM     | 100+ Manufacturing/Coyote                          | ASC      |
| DPQS     | 10C Technologies Inc                               | AQW      |
| DPQS     | 10C Technologies Inc                               | ASQ      |
| FDJG     | 2 Cool AirVents                                    | CAS      |

我试图让结果看起来像：

   +----------+----------------------------------------------------+-------+-------+-------+-------+-------+-------+-------+-------+-------+--------+
| brand_id | brand_name                                         | Code1 | Code2 | Code3 | Code4 | Code5 | Code6 | Code7 | Code8 | Code9 | Code10 |
+----------+----------------------------------------------------+-------+-------+-------+-------+-------+-------+-------+-------+-------+--------+
| DPQT     | 1-800 Tow Truck                                    | DCF   | DCA   | AAA   | DDD   | DER   | NULL  | NULL  | NULL  | NULL  | NULL   |
| BLGR     | 1-800-Radiator                                     | Curt  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL   |
| BGVM     | 100+ Manufacturing/Coyote                          | ASC   | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL   |
| DPQS     | 10C Technologies Inc                               | ASQ   | AQW   | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL   |
| FDJG     | 2 Cool AirVents                                    | CAS   | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL   |

如您所见，当品牌 ID 和品牌名称相同时，我想将行代码分组到单独的列中

最大行代码将是 10。这就是为什么我有 Code1-Code10

这就是我现在正在做的事情，但它不起作用。

$sql0 = 'set @num := 0';
$result = mysqli_query($dbh,"select brand_id,   brand_name,   
max(case when group_row_number = 1 then linecode end) Code1,   
max(case when group_row_number = 2 then linecode end) Code2,   
max(case when group_row_number = 3 then linecode end) Code3,   
max(case when group_row_number = 4 then linecode end) Code4,   
max(case when group_row_number = 5 then linecode end) Code5,   
max(case when group_row_number = 6 then linecode end) Code6,  
max(case when group_row_number = 7 then linecode end) Code7,   
max(case when group_row_number = 8 then linecode end) Code8,   
max(case when group_row_number = 9 then linecode end) Code9,   
max(case when group_row_number = 10 then linecode end) Code10 
from (  select brand_id, brand_name, linecode, @num := @num + 1 as group_row_number from linecodes_temp ) src 
group by brand_id, brand_name 
order by if(linecode = '' or linecode is null,1,0), brand_name ASC");

我得到的结果是

+----------+----------------------------------------------------+-------+-------+-------+-------+-------+-------+-------+-------+-------+--------+
| brand_id | brand_name                                         | Code1 | Code2 | Code3 | Code4 | Code5 | Code6 | Code7 | Code8 | Code9 | Code10 |
+----------+----------------------------------------------------+-------+-------+-------+-------+-------+-------+-------+-------+-------+--------+
| DPQT     | 1-800 Tow Truck                                    | DER   | DCF   | DCA   | AAA   | DDD   | NULL  | NULL  | NULL  | NULL  | NULL   |
| BLGR     | 1-800-Radiator                                     | NULL  | NULL  | NULL  | NULL  | NULL  | Curt  | NULL  | NULL  | NULL  | NULL   |
| BGVM     | 100+ Manufacturing/Coyote                          | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | ASC   | NULL  | NULL  | NULL   |
| DPQS     | 10C Technologies Inc                               | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | AQW   | ASQ   | NULL   |
| FDJG     | 2 Cool AirVents                                    | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | NULL  | CAS    |

我需要一种方法，这样一旦brand_id 和brand_name 更改，num 变量就会回到0。

正如您所看到的，它正在做我想要它做的事情，但是一旦它进入下一行，num 变量就会继续上升到下一列。那么这就是添加下一行代码的地方。我假设我需要在某些地方使用 if 语句，但我不明白该怎么做。

如果有人可以更新我的查询以便发生这种情况，我将非常感激

感谢您的时间。

4

3 回答 3

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您说的是部分转置，PHP 不会自动执行。但是，您可以自己进行一些小的修改。

在您的查询中，使用GROUP_CONCAT()：

SELECT brand_id, brand_name, GROUP_CONCAT(linecode) AS codes brands GROUP BY brand_id, brand_name

在 PHP 中，用于explode()获取不同的代码：

$codes = explode(',', $row['codes']);

注意：我对您的基础表结构做了一些假设。相应地调整查询。

于 2012-12-03T18:57:28.867 回答
0 
select a.name,a.value,a.code,T.code  from test1 as a INNER JOIN test1 as T on  
a.name=T.name and a.value = T.value and a.code != T.code  group by a.name;

Try this. I have assumed that your brand name and brand id are always going to be the same. If they are going to be different , they remove the check for brand names.

This one is just an idea of what the query should be . U can tweak this to get better results

于 2012-12-03T19:52:44.403 回答
0

编辑：如果你必须完全在 MySQL 中完成，这并不漂亮，但是......

SELECT 
    a.brand_id, a.brand_name, b.linecode AS code1, c.linecode AS code2, d.linecode AS code3, e.linecode AS code4, f.linecode AS code4 FROM test a 
LEFT JOIN 
    test b ON b.brand_id = a.brand_id 
LEFT JOIN 
    test c ON c.brand_id = b.brand_id AND b.linecode != c.linecode
LEFT JOIN 
    test d ON d.brand_id = c.brand_id AND d.linecode != c.linecode AND d.linecode != b.linecode
LEFT JOIN 
    test e ON e.brand_id = d.brand_id AND e.linecode != d.linecode AND e.linecode != c.linecode AND e.linecode != b.linecode
LEFT JOIN 
    test f ON f.brand_id = e.brand_id AND f.linecode != e.linecode AND f.linecode != d.linecode AND f.linecode != c.linecode AND f.linecode != b.linecode
GROUP BY 
    a.brand_id
ORDER BY 
    a.brand_id

重复 LEFT JOIN 直到您有 10 个代码列。

于 2012-12-03T20:13:52.270 回答