1

我正在尝试运行以下代码：

SELECT a.job_name
     , coalesce(b.target_time, cast('08:00:00' as time(2))) sla_time

FROM ud812.slarpt_job_level_info a
left outer join ( 
   select job_name, target_time
   from ud812.slarpt_job_target_times 
   qualify row_number() over (partition by job_name 
                              order by established_date desc) = 1
   ) b
on (a.job_name = b.job_name)
where  a.display_on_sla_report = 'Y' 
   and a.job_type = 'LD'
   and a.decom_date is null

这样做时，我收到错误“选择失败 3800：THEN/ELSE 表达式中的数据类型不匹配。这与我对合并的使用有关。

当我检查我的数据类型时：从 ud812.slarpt_job_target_times 中选择 type(target_time) 合格...我得到 time(2)。我已经尝试了几件事来调整我的代码。

其中包括： 使用不同的数据类型 ex。时间（6）。我什至尝试了以下方法，但 sla_time 的类型返回为整数。

SELECT a.job_name
      , cast(coalesce(b.target_time, '08:00:00') as time(2)) sla_time

FROM ud812.slarpt_job_level_info a
left outer join ( 
   select job_name, cast(target_time as char(8)) as target_time
   from ud812.slarpt_job_target_times 
   qualify row_number() over (partition by job_name 
                              order by established_date desc) = 1
   ) b
on (a.job_name = b.job_name)
where  a.display_on_sla_report = 'Y' 
   and a.job_type = 'LD'
   and a.decom_date is null

最后，我试图为每个工作名称设定一个默认时间为早上 8 点。想法？

我也尝试了以下方法，但是当我键入（）该列时，它返回一个整数，而不是时间（2）。

SELECT a.job_name
     , cast(coalesce(b.target_time, default_time) as time(2)) sla_time
FROM ( 
   select job_name, '08:00:00' as default_time
   from ud812.slarpt_job_level_info
   where  a.display_on_sla_report = 'Y' 
     and a.job_type = 'LD'
     and a.decom_date is null
   ) a
left outer join ( 
   select job_name, target_time
   from ud812.slarpt_job_target_times 
   qualify row_number() over (partition by job_name 
                              order by established_date desc) = 1
   ) b
on (a.job_name = b.job_name)
4

1 回答 1

0

在下面的测试用例中，COALESCE()当您使用格式TIME '00:00:01'作为 NULL 的替换值时。

CREATE VOLATILE TABLE MyTable, NO FALLBACK
( MyID SMALLINT NOT NULL,
  MyTime TIME(2)
)
PRIMARY INDEX (MyID) 
ON COMMIT PRESERVE ROWS;

INSERT INTO MyTable VALUES (1, TIME '01:23:45');
INSERT INTO MyTable VALUES (2, NULL);

SELECT *
FROM MyTable;

SELECT MyID
     , COALESCE(MyTime, TIME '23:45:01')
 FROM MyTable;
于 2013-01-09T17:35:49.813 回答