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我的问题是我在弹出窗口中创建了一个列表框，并设置弹出窗口的staysopen = false。但是每次弹出框弹出时，我都必须单击弹出框内的某些内容（例如在列表框中选择一个元素），然后单击弹出框外部，它会自动关闭。如果我不点击任何东西，即使我点击弹出窗口之外的其他元素，弹出窗口也会保持打开状态。我需要关闭弹出窗口而不需要我单击其中的任何元素。我能做些什么？这是代码，此代码还有一些其他样式链接，但只是一些颜色样式。

我的控制是当用户单击弹出框顶部的文本框时，列表框会弹出。如果用户什么都不做并单击此元素之外的任何位置，则弹出框将关闭。谢谢。

我可以使用下面的代码在 Silverlight 中完成它。但似乎在 wpf 中，它不再工作了。

popupAncestor = FindHighestAncestor(this.ListBoxPopup); if (popupAncestor == null) { return; } popupAncestor.AddHandler(System.Windows.Controls.Primitives.Popup.MouseLeftButtonDownEvent, (MouseButtonEventHandler)ClosePopup, true);

<Grid x:Name="MainGrid" Margin="0" VerticalAlignment="Center">
    <Grid.RowDefinitions>
        <RowDefinition Height="20"></RowDefinition>
        <RowDefinition Height="auto"></RowDefinition>
    </Grid.RowDefinitions>
    <Grid Margin="1,1,1,0" x:Name="TopBar"  Visibility="Visible"  Grid.Row="0" Height="20" VerticalAlignment="Stretch" HorizontalAlignment="Stretch" Background="{StaticResource COL_BTN_LIGHT}">
        <Grid.ColumnDefinitions>
            <ColumnDefinition Width="*"></ColumnDefinition>
            <ColumnDefinition Width="19"></ColumnDefinition>
        </Grid.ColumnDefinitions>
        <TextBox x:Name="TextBoxSearchItem"  x:FieldModifier="private" HorizontalAlignment="Stretch" Grid.Column="0" VerticalAlignment="Stretch" BorderThickness="0,0,0,0" Background="Transparent" TextChanged="TextBoxSearchItem_TextChanged"></TextBox>
        <ToggleButton x:Name="DropDownArrorButton" Grid.Column="1" Style="{StaticResource ComboBoxReadonlyToggleButton}"></ToggleButton>
        <!--<TextBlock HorizontalAlignment="Center" Text="Search" Grid.ColumnSpan="2" TextBlock.FontStyle="Italic" Opacity="0.4" VerticalAlignment="Center"/>-->
    </Grid>
    <Grid Grid.Row="1" HorizontalAlignment="Stretch" x:Name="PopupGrid"  Margin="0,1,0,0" >
        <Popup x:Name="ListBoxPopup" StaysOpen="False" x:FieldModifier="private"  IsOpen="{Binding ElementName=DropDownArrorButton, Path=IsChecked, Mode=TwoWay}" 
               AllowsTransparency="true" Margin="0" HorizontalAlignment="Stretch" Placement="Bottom" 
               PlacementTarget="{Binding ElementName=TopBar}"  Opened="OnPopupOpened" Closed="OnPopupClosed"
               HorizontalOffset="{Binding ElementName=PopupGrid, Path=Value, Mode=TwoWay}"
                 VerticalOffset="{Binding ElementName=PopupGrid, Path=Value, Mode=TwoWay}">
            <ListBox x:Name="ListBoxContainer" Width="{Binding ElementName=MainGrid, Path=ActualWidth}" 
                     HorizontalContentAlignment="Stretch" SelectionMode="Single"  Height="200"  Margin="0" 
                     SelectionChanged="ListBoxContainer_SelectionChanged"
                     MouseDoubleClick="ListBoxContainer_MouseDoubleClick">
                <ListBox.ItemTemplate>
                    <DataTemplate>
                        <Grid HorizontalAlignment="Stretch">
                            <Border BorderBrush="{Binding SearchedBackColor}" BorderThickness="{Binding Indicator}" Width="{Binding ElementName=MainGrid, Path=ActualWidth}">
                                <TextBlock x:Name="ContentText" Text="{Binding Name}" Margin="1,0,0,0"/>
                            </Border>                               
                        </Grid>
                    </DataTemplate>
                </ListBox.ItemTemplate>
            </ListBox>
        </Popup>                
        <Border x:Name="listBorder" BorderBrush="{StaticResource COL_BTN}" BorderThickness="0,1,0,0" ></Border>     
    </Grid>                 
</Grid>
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1 回答 1

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您应该在视图模型或控件中为“IsPopupOpen”创建一个依赖属性，如下所示来管理弹出窗口的状态。然后，您可以将 ToggleButton“IsChecked”和弹出“IsOpen”绑定到该 DP。

同样在您的 ToggleButton 上，设置“Focusable=false”和“IsThreeState=false”

    public bool IsDropDownOpen
    {
     get { return (bool)GetValue(IsDropDownOpenProperty); }
     set { SetValue(IsDropDownOpenProperty, value); }
    }        

    public static readonly DependencyProperty IsDropDownOpenProperty =
          DependencyProperty.Register("IsDropDownOpen", typeof(bool), typeof(Window), new UIPropertyMetadata(false));

祝你好运！

于 2013-02-11T16:22:11.097 回答