0

知道为什么 Matlab 会这样吗？

>> sum([0 0 0])
Subscript indices must either be real positive integers or logicals.

>> sum([1 1 1])

ans =

     4     4     4

和这个打了2个多小时，还是搞不定。这是我在这发生之前运行的代码。在运行此代码之前 - 函数 sum() 工作正常。

price = 100;
vola = 0.2;
r = 0.05;
n_step = 3;
dt = 1/250;
S0 = 100;
T = 1;

s = [1 0 0 0;1 2 0 0;1 2 3 0; 1 2 3 4];
prob = 0.5;
n_path = 2^n_step; % bottle neck for binomial approach
avg_price = zeros(n_path, 2); % first column - probability, second - average price
path_matrix = zeros(n_path, n_step); % all possible paths 1-up, 0-down
for k = 0:n_path-1
    path_matrix(k+1, :) = de2bi(k,'left-msb',n_step);
end

node_matrix = path_matrix;
for k=2:n_step
    node_matrix(:, k) = node_matrix(:, k-1) + node_matrix(:, k);
end
node_matrix = node_matrix + 1;

% go through all possible paths and calculate sum of prices
for k = 1:n_path
    % probability of path
    n_up = sum(path_matrix(k, :));
    avg_price(k, 1) = prob^n_up*(1 - prob)^(n_step - n_up);

    % get sum of prices over all states for this path
    sum = s(1, 1);
    for p = 1:n_step
        sum = sum + s(p+1, node_matrix(k, p));
    end
    avg_price(k, 2) = sum;
end
4

1 回答 1

2

您已经覆盖了该函数sum，现在它被视为局部变量

 sum = s(1, 1);

因此，您隐藏 sum为功能。

更改变量名并执行

 clear sum

.

于 2012-12-02T18:49:54.073 回答