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我正在向sturct dataBlock我的线程发送一个，其中包含a pointer相同的 listRoot（对于所有线程）、一个int indexInForLoop和一个int listSize；列表中的节点有一个 int 值，它是要处理的 ash 和一个 int worker，它是 nrOfListElements % nrOfWorkers(Threads)。但不知何故，我发送给每个线程的结构是相同的，但它不应该每个都有 1 个不同的 int 变量和 indexFromForLoop。我究竟做错了什么？

终端输出：

node #1 worker: 1  value: 86
node #2 worker: 0  value: 77
node #3 worker: 1  value: 15
node #4 worker: 0  value: 93
node #5 worker: 1  value: 35
? List got populated
workersInput: 2
in for, ret= 0
in for, ret= 0
* Thread start:             id: 3067579200^
forID_ 1 
->val: 86   
valid for sqrt 
* Thread start:             id: 3075971904^
forID_ 1 
->val: 86   
valid for sqrt

代码：

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>
#include <math.h>   

#define workTime 5
#define workersLimitNr 3

struct dataBlock{
    struct node *root;
    int listSize;
    int forIndex;
};

struct node { // std linked list node
    int value;
    int worker;
    struct node *next;
};

int slots = 0; // only 3 threads are allowed to access the list
int availableCheck(){   // check if thread can acces the list
    if(slots < 3) return 0;
    else return -1;
}

pthread_mutex_t mutp = PTHREAD_MUTEX_INITIALIZER;   //condvar mutex
pthread_cond_t  condvar = PTHREAD_COND_INITIALIZER;   //condvar

void * worker( void *data ){
    struct dataBlock *inData = (struct dataBlock *) data;
    struct node *root = inData->root;
    int listSize =  inData->listSize;
    int forIndex = inData ->forIndex;

    printf( "* Thread start:            ^\n"); 

    pthread_mutex_lock( &mutp );
    if(availableCheck() < 0){
        printf( " ^^^ List not available yet... \n" ); 
        pthread_cond_wait( &condvar, &mutp );
    } 
    struct node *it = root;
    printf("forID_ %d \n", forIndex);
    while(it->next != NULL){
        if(forIndex == it->worker){
            printf("valid for sqrt \n");
            if(it->value > 2){
                sqrt(it->value);
                break;
            }
        }
        it = it->next;
        printf("->val: %d   \n", it->value);
    }

    pthread_cond_signal( &condvar ); // 
    pthread_mutex_unlock( &mutp ); 
    return NULL;
}

int main( int argc, char *argv[] ){
    if ( argc != 3 ){
        printf( "Programm must be called with \n NR of elements and NR of workers! \n " );
        exit( 1 );
    }

    int i;
    struct node *root;
    struct node *iterator;  

//prepare list for task
    int listSize = atoi(argv[1]);
    int nrWorkers = atoi(argv[2]);
    root = malloc(sizeof( struct node) );

    root->value = rand() % 100;
    root->worker = 0;
    iterator = root;

    for( i=1; i<listSize; i++ ){
        iterator->next = malloc(sizeof(struct node));
        iterator = iterator->next;
        iterator->value = rand() % 100;
        iterator->worker = i % nrWorkers;
        printf("node #%d worker: %d  value: %d\n", i, iterator->worker,iterator->value);
    }
    printf("? List got populated\n");

// Create all threads to parse the link list
    int ret;    
    printf("workersInput: %d\n",nrWorkers);

    pthread_t w_thread;
    pthread_t* w_threads = malloc(nrWorkers * sizeof(w_thread));

    struct dataBlock *data = malloc(sizeof(struct dataBlock));
    data->root = root;
    data->listSize = listSize;

    for( i=0; i < nrWorkers; i++ ){ 
        data->forIndex = i;
        ret = pthread_create ( &w_threads[i], NULL, worker, (void *) data );
        if( ret ) {
            perror("Thread creation fail");
            exit(2);    
        }   
        printf("in for, ret= %d\n",ret);
    } 

    for ( i = 0; i < nrWorkers; i++){
        pthread_join(w_threads[i],NULL);
    }

    free(root);
    free(iterator);
    return 0;
}

编辑：我使用了 pthread_self() 并确认存在不同的威胁

4

1 回答 1

1

使用

data->forIndex = i;

您覆盖以前的值。并且由于您只有一个dataBlock线程，因此每个线程都会指向同一个地方。而且由于创建线程并不意味着“在执行循环中的下一条语句之前启动它”，因此每个线程看到的值纯属运气。

您必须dataBlock为每个线程分配一个，并且dataBLock只将每个线程分配给一个线程。

于 2012-12-01T21:32:56.790 回答