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Since in log4j javadoc is

WARNING: This version of JDBCAppender is very likely to be completely replaced in the future. Moreoever, it does not log exceptions.

What should I do to log to a database?

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3 回答 3

33

如果您正在寻找一个不仅可以工作，而且还支持连接池、维护和正确记录的数据库附加程序，那么请考虑 logback 的DBAppender。

具有讽刺意味的是，javadocs 中关于在 log4j 的未来版本中删除 JDBCAppender 的警告是我写的。

于 2009-09-02T09:32:05.390 回答
11

You can use an alternative appender, but really Log4j 1.2 is going to be around and standard for a long time. They developed DBAppender as part of their receivers companions, which isn't officially released, but you can download the source code and get your own going as well.

Unless the issue of not logging exceptions bothers you, JDBCAppender is just fine. Any further upgrade to 2.0 is going to be more radical than just changing JDBCAppender (if 2.0 happens), so I wouldn't worry about using it, despite the warning. They clearly don't have a solid roadmap or timeline to introducing a new version, and 1.2.15 was released in 2007.

于 2009-09-01T20:06:21.650 回答
0 
    **log4j.properties file**

    # Define the root logger with appender file
    log4j.rootLogger = DEBUG, DB

    # Define the DB appender
    log4j.appender.DB=org.apache.log4j.jdbc.JDBCAppender

    # Set JDBC URL
    log4j.appender.DB.URL=jdbc:mysql://localhost/log

    # Set Database Driver
    log4j.appender.DB.driver=com.mysql.jdbc.Driver

    # Set database user name and password
    log4j.appender.DB.user=root
    log4j.appender.DB.password=root

    # Set the SQL statement to be executed.
    log4j.appender.DB.sql=INSERT INTO actionlg(user_id, dated, logger, level, message) values('%X{userId}',' %d{yyyy-MM-dd-HH-mm}','%C','%p','%m')

    # Define the layout for file appender
    log4j.appender.DB.layout=org.apache.log4j.PatternLayout

  **Java Class**  
    Log4jExamples.java
    import java.sql.*;
    import java.io.*;

    import org.apache.log4j.Logger;
    import org.apache.log4j.MDC;


    public class Log4jExample {
           /* Get actual class name to be printed on */
           static Logger log = Logger.getLogger(Log4jExample.class.getName());
           public static void main(String[] args)throws IOException,SQLException{
              log.error("Error");
              MDC.put("userId", "1234");
           }
    }

    **libs required**
     - mysql-connector-java-3.1.8-bin.jar 
     - log4j-1.2.17.jar
于 2015-06-26T11:21:56.480 回答