1

我最好先查询下面列出的查询，然后按分组stories.id，但我收到以下错误：

ERROR: column "u.first_name" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: SELECT "s".*, "u"."first_name", "u"."last_name", ("i"."filen...

第二个查询有效，但不分组stories.id并生成错误的结果。是否可以从多个表中选择而不是按所有表分组？

该表panels也有一列updated_at。我想file根据panels.updated_at.

   SELECT 
        "s".*, 
        "u"."first_name", 
        "u"."last_name", 
        ("i"."filename" || '.' || "i"."extension") AS "file" 
    FROM 
        "stories" "s" 
    LEFT JOIN "panels" "p" ON("p"."story_id" = "s"."id") 
    LEFT JOIN "users" "u" ON("s"."user_id" = "u"."uid")
    LEFT JOIN "images" "i" ON ("p"."image_id" = "i"."id") 
    WHERE 
        "s"."complete" = false AND 
        "s"."created_by" = 205700489 
    GROUP BY 
        "s"."id", 
    ORDER BY 
        "s"."created_at" DESC

   SELECT 
        "s".*, 
        "u"."first_name", 
        "u"."last_name", 
        ("i"."filename" || '.' || "i"."extension") AS "file" 
    FROM 
        "stories" "s" 
    LEFT JOIN "panels" "p" ON("p"."story_id" = "s"."id") 
    LEFT JOIN "users" "u" ON("s"."user_id" = "u"."uid")
    LEFT JOIN "images" "i" ON ("p"."image_id" = "i"."id") 
    WHERE 
        "s"."complete" = false AND 
        "s"."created_by" = 205700489 
    GROUP BY 
        "s"."id", 
        "u"."first_name", 
        "u"."last_name", "i"."filename", 
        "i"."extension" 
    ORDER BY 
        "s"."created_at" DESC
4

2 回答 2

2

澄清问题后更新：

SELECT DISTINCT ON (s.created_at, s.id)
       s.*
      ,u.first_name
      ,u.last_name
      ,concat_ws('.', i.filename, i.extension) AS file
FROM   stories s 
LEFT   JOIN users  u ON u.uid = s.user_id
LEFT   JOIN panels p ON p.story_id = s.id
LEFT   JOIN images i ON i.id = p.image_id
WHERE  s.complete = false
AND    s.created_by = 205700489 
ORDER  BY s.created_at DESC, s.id, p.updated_at DESC;

按主键分组需要 PostgreSQL 9.1。
我使用concat_ws(), 因为我不知道哪些列可能是NULL. 如果同时定义i.filename和，则可以简化。i.extensionNOT NULL

附加ORDER BY项目的效果是每个故事都会选择p.updated_at DESC“最新” 。file在这个相关问题下完整解释了查询技术：
Select first row in each GROUP BY group?

于 2012-11-29T15:47:37.017 回答
0

您可以编写如下内容：

   SELECT 
        "s".*, 
        (SELECT "u"."first_name" 
         FROM "users" "u"
         WHERE "s"."user_id" = "u"."uid"
         LIMIT 1) , 
        (SELECT "u"."last_name" 
         FROM "users" "u"
         WHERE "s"."user_id" = "u"."uid"
         LIMIT 1), 
        (SELECT "i"."filename" || '.' || "i"."extension"
         FROM "panels" "p" 
         JOIN "images" "i" ON ("p"."image_id" = "i"."id")
         WHERE "p"."story_id" = "s"."id" 
         LIMIT 1) AS "file" 
    FROM 
        "stories" "s" 
    WHERE 
        "s"."complete" = false AND 
        "s"."created_by" = 205700489 
    ORDER BY 
        "s"."created_at" DESC

它只会从 中的每条记录中获取 1"users"条"panels" JOIN "images"记录"stories"。

添加ORDER BY，额外WHERE或一些聚合以获取您需要的内容"users"和"panels" JOIN "images"

UPD 此外，您可以使用以下内容：

SELECT *
FROM (
SELECT DISTINCT ON ("s"."id") 
    "s".*, 
    "u"."first_name", 
    "u"."last_name", 
    ("i"."filename" || '.' || "i"."extension") AS "file" 
FROM 
    "stories" "s" 
LEFT JOIN "panels" "p" ON("p"."story_id" = "s"."id") 
LEFT JOIN "users" "u" ON("s"."user_id" = "u"."uid")
LEFT JOIN "images" "i" ON ("p"."image_id" = "i"."id") 
WHERE 
    "s"."complete" = false AND 
    "s"."created_by" = 205700489 
ORDER BY 
    "s"."id"
) t ORDER BY "t"."created_at" DESC

它只会为每个不同的"s"."id"

于 2012-11-29T13:58:31.450 回答