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我有一个模型，我创建并传递给我的视图。该模型创建了一个表单并使用该HttpPost属性将模型取回。我将模型保存到数据库，然后我想将默认模型状态返回到视图（IE 下拉值，但不是所选项目）

我创建了一个空模型，将其传递给视图，但值保持不变，我不明白为什么。

我的观点

 @using (Html.BeginForm())
  {
    @Html.ValidationSummary(true)
    <fieldset>
      <legend>
        <h2>Configuration settings</h2>
      </legend>

      <div class="editor-label">
        @Html.LabelFor(model => model.DeviceType)
      </div>
      <div class="editor-field">
        @Html.DropDownListFor(model => model.DeviceTypeSelectedItem, new SelectList(Model.DeviceType, "Value", "Text"),new {@class = "DeviceTypeDDL"})
        @Html.ValidationMessageFor(model => model.DeviceTypeSelectedItem)
      </div>

       <div class="editor-label">
        @Html.LabelFor(model => model.ConfigGroup)
      </div>
      <div class="editor-field">
        @Html.DropDownListFor(model => model.ConfigGroupSelectedItem, new SelectList(Model.ConfigGroup, "Value", "Text"),new {@class = "ConfigGroupDDL"})
        @Html.ValidationMessageFor(model => model.ConfigGroupSelectedItem)
      </div>

       <div class="editor-label">
        @Html.LabelFor(model => model.ConfigName)
      </div>
      <div class="editor-field">
        @Html.DropDownListFor(model => model.ConfigNameSelectedItem, new SelectList(Model.ConfigName, "Value", "Text"),new {@class = "ConfigNameDDL"})
        @Html.ValidationMessageFor(model => model.ConfigNameSelectedItem)
      </div>

        <div class="editor-label">
        @Html.LabelFor(model => model.ConfigValue)
      </div>
      <div class="editor-field">
        @Html.EditorFor(model => model.ConfigValue)
        @Html.ValidationMessageFor(model => model.ConfigValue)
      </div>

        <div class="editor-label">
        @Html.LabelFor(model => model.MergeOrDelete)
      </div>
      <div class="editor-field">
        @Html.DropDownListFor(model => model.MergeOrDeleteSelectedItem, new SelectList(Model.MergeOrDelete, "Value", "Text"), new { @class = "MergeDeleteDDL" })
        @Html.ValidationMessageFor(model => model.MergeOrDeleteSelectedItem)
      </div>

      @Html.HiddenFor(model => model.ManagementGroupId)

      <p>
        <input type="submit" value="Add" />
      </p>
    </fieldset>
  }

控制器：

[HttpGet]
    public ActionResult Index(int id)
    {
      var model = CreateDefaultConfigModel(id);
      return View(model);
    }
    [HttpPost]
    public ActionResult Index(vmConfiguration model)
    {
      if (ModelState.IsValid)
      {
        bool isMerge = model.MergeOrDeleteSelectedItem == 1 ? true : false;
        _configLogic.AddConfigurationValue((int)model.ConfigNameSelectedItem, (int)model.ManagementGroupId, model.ConfigValue, isMerge);
        return View(CreateDefaultConfigModel(model.ManagementGroupId));
      }
      else
      {
        return View(model);
      }
    }
private vmConfiguration CreateDefaultConfigModel(int id)
{
  var model = new vmConfiguration
  {
    DeviceType = _configLogic.GetDevices,
    ConfigGroup = new List<SelectListItem>() { EmptySelect() },
    ConfigName = new List<SelectListItem>() { EmptySelect() },
    ConfigGroupSelectedItem = null,
    MergeOrDeleteSelectedItem = null,
    DeviceTypeSelectedItem = null,
    ConfigNameSelectedItem = null,
    ManagementGroupId = id,
    ParamData = _configLogic.GetParamValuesForGroup(id)
  };
  return model;
}
private static SelectListItem EmptySelect()
{
  return new SelectListItem { Text = "No value", Value = "-1" };
}
private ConfigurationLogic _configLogic;

做研究我发现如果我this.ModelState.Clear();在创建新模型之前调用它，那么它可以工作，但为什么 MVC 会忽略我传递的模型并使用绑定的模型？

4

1 回答 1

3

改变

return View(CreateDefaultConfigModel(model.ManagementGroupId));

对此

return RedirectToAction("Index", new { id = model.ManagementGroupId });

它不会忽略您的模型，它会在您将它们发送回同一索引页面时尝试填写您的表单，因为它假设您由于需要更多信息而将它们发送回来，并且它试图通过不强迫用户重新来提供帮助- 再次输入所有信息。此信息全部存储在 ModelState 中，因为它保存了回传到服务器的尝试值。无论如何，在成功发布后重定向是推荐的模式。查找PRG 模式

于 2013-02-27T22:22:18.807 回答