iphone - iOS<6中访问通讯录出错

Question

我已经实现了获取联系人的方法。

对于 iOS 6，我使用下面的代码来获得用户的许可：

CFErrorRef myError = NULL;
ABAddressBookRef myAddressBook = ABAddressBookCreateWithOptions(NULL, &myError);
ABAddressBookRequestAccessWithCompletion(myAddressBook,^(bool granted, CFErrorRef error)
{
   if(granted)
    {
        [self GetContactInformation];
    }
   else
    {
        UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Contacts" message:@"You didn't permit us to access your contact details." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil];
        [alert show];
        [alert release];
    }
});
CFRelease(myAddressBook);

上面的代码在 iOS 6 中工作正常，但在 iOS 6 下我得到以下错误：

Answer 1

您可以使用 MACROS 进行过滤：

#if __IPHONE_OS_VERSION_MAX_ALLOWED >= 60000
CFErrorRef myError = NULL;
ABAddressBookRef myAddressBook = ABAddressBookCreateWithOptions(NULL, &myError);
ABAddressBookRequestAccessWithCompletion(myAddressBook,^(bool granted, CFErrorRef error)
{
   if(granted)
    {
        [self GetContactInformation];
    }
   else
    {
        UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Contacts" message:@"You didn't permit us to access your contact details." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil];
        [alert show];
        [alert release];
    }
});
CFRelease(myAddressBook); 
#else
    [self GetContactInformation];
#endif

让我们知道它是否有效。

Answer 2

好吧，看来你已经知道答案了。这两个函数都仅限于 iOS 6+ ，并且在之前的 SDK 中不存在，这意味着它们的符号是未定义的。你必须编码到最小的公分母，或者将你的目标提高到 iOS 6。