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我想以字符串“2012-11-22 10:19:04”中的“20-Sep-2012”格式显示日期。我怎样才能做到这一点？iOS有什么内置方法吗？

4

5 回答 5

59 
NSString *myString = @"2012-11-22 10:19:04";
NSDateFormatter* dateFormatter = [[NSDateFormatter alloc] init];
dateFormatter.dateFormat = @"yyyy-MM-dd HH:mm:ss";     
NSDate *yourDate = [dateFormatter dateFromString:myString];
dateFormatter.dateFormat = @"dd-MMM-yyyy";
NSLog(@"%@",[dateFormatter stringFromDate:yourDate]);

您的日志将像这样打印。22-Nov-2012

于 2012-11-22T05:00:57.323 回答
6

尝试这个，

NSString *originalDateString = @"2012-11-22 10:19:04";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"];//2012-11-22 10:19:04

然后用它来解析日期字符串，

NSDate *date = [dateFormatter dateFromString:originalDateString];

您可以创建一个新的 dateformatter 以新格式打印，或者只是将现有格式重用为，

[dateFormatter setDateFormat:@"dd-MMM-yyyy"];//22-Nov-2012
NSString *formattedDateString = [dateFormatter stringFromDate:date];
NSLog(@"Date in new format is %@", formattedDateString);
于 2012-11-22T05:00:41.503 回答
2

Swift 3中 (@Dinesh Raja) 接受的答案：

override func viewDidLoad() {
super.viewDidLoad()
    print(self.getFormattedDate(myString: "2012-11-22 10:19:04"))
}

func getFormattedDate(myString: String) -> String{
        let dateFormatter = DateFormatter()
        dateFormatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
        let yourDate = dateFormatter.date(from: myString)!
        dateFormatter.dateFormat = "dd-MMM-yyyy"
        return dateFormatter.string(from: yourDate)
    }
于 2016-10-13T07:45:38.123 回答
0

尝试这个

    NSString *str = @"2012-11-22 10:19:04";

    NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
    [dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"];

    NSDate *date = [dateFormatter dateFromString: str];

    dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
    [dateFormatter setDateFormat:@"dd-MMM-yyyy"];

    NSString *convertedString = [dateFormatter stringFromDate:date];
    NSLog(@"Converted String : %@",convertedString);// Print Log (Output) is 22-Nov-2012

用这种方法查看我的博客所有信息我的博客链接

于 2012-11-22T05:01:28.400 回答
0

您可以通过以下方式实现此目的

      NSDateFormatter *dfTime = [[NSDateFormatter alloc] init];
      [dfTime setDateFormat:@"yyyy--MM-dd HH:mm:ss"];
      NSDate *dtTime = [dfTime dateFromString:<Your string>];
      NSDateFormatter *df = [[NSDateFormatter alloc] init];
      [df setDateFormat:@"dd-MMM-yyyy"];
       <Your result string> = [df stringFromDate:dtTime];

Where <Your string> = @"2012-11-22 10:19:04" & 
<Your result string> will be your new string

享受编程

于 2012-11-22T05:01:35.467 回答