matplotlib - matplotlib 极坐标 2d 直方图

Question

我正在尝试在极轴上绘制一些直方图数据，但它似乎无法正常工作。下面是一个示例，我使用自定义投影找到 如何使 matplotlib 极坐标图中的角度顺时针旋转，顶部为 0°？它适用于散点图，所以我认为我的问题在于直方图函数。这让我整天发疯，有谁知道我做错了什么............

import random
import numpy as np
import matplotlib.pyplot as plt

baz = np.zeros((20))
freq = np.zeros((20))
pwr = np.zeros((20))
for x in range(20): 
    baz[x] = random.randint(20,25)*10
    freq[x] = random.randint(1,10)*10
    pwr[x] = random.randint(-10,-1)*10
baz = baz*np.pi/180.  

abins = np.linspace(0,2*np.pi,360)      # 0 to 360 in steps of 360/N.
sbins = np.linspace(1, 100) 
H, xedges, yedges = np.histogram2d(baz, freq, bins=(abins,sbins), weights=pwr)

plt.figure(figsize=(14,14))
plt.subplot(1, 1, 1, projection='northpolar')
#plt.scatter(baz, freq)
plt.pcolormesh(H)
plt.show()

Answer 1

如果您将 mgrid（具有与您的 a bin 和 sbin 相似的特征）明确传递给 pcolormesh 命令，则您的代码可以工作。

以下是受您的代码启发的示例：

import matplotlib.pyplot as plt
import numpy as np

#Generate the data
size = 200

baz = 10*np.random.randint(20, 25, size)*np.pi/180.
freq = 10*np.random.randint(1, 10, size)
pwr = 10*np.random.randint(-10, -1, size)

abins = np.linspace(0, 2*np.pi, 360)      # 0 to 360 in steps of 360/N.
sbins = np.linspace(1, 100, 50) 
H, xedges, yedges = np.histogram2d(baz, freq, bins=(abins,sbins), weights=pwr)

#Grid to plot your data on using pcolormesh
theta, r = np.mgrid[0:2*np.pi:360j, 1:100:50j]

fig, ax = plt.subplots(figsize=(14,14), subplot_kw=dict(projection='northpolar'))
ax.pcolormesh(theta, r, H)

ax.set_yticklabels([]) #remove yticklabels

plt.show()