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我有大量嵌入在文档中的数字数据集。我想把它们全部提取出来，把它们放在一个有序列表中，然后将它的“pvalue”返回到每个文档：这是它在排序列表中的顺序除以列表的长度。我在弄清楚如何在 python 代码中执行此操作时遇到了很多麻烦。

movie_records = db.movies.find()
list=[]

for i in movie_records:
    num = i["total_tickets"]

    #put them all in a list, order the list


for i in movie_records:
    number=i["total_tickets"]
    tickets_pvalue= 1 - ( #position of number /len(list) )
    shows.update({"id":i["id"]}, {'$set':{"total_tickets_pvalue":tickets_pvalue}})
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1 回答 1

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除非对 mongodb 有任何了解（最好按照评论中的建议进行排序）：

movie_records = sorted([(m['total_tickets'], m) for m in db.movies.find()])

# Select distinct on total_tickets
distinct_records = []
prev = None
while movie_records:
    record = movie_records.pop(0)
    if record[0] != prev:
        prev = record[0]
        distinct_records.append(record[1])

for index, movie in enumerate(distinct_records):
    tickets_pvalue = 1 - (index + 1.0) / len(distinct_records)
    shows.update({"id": movie["id"]},
                 {'$set': {"total_tickets_pvalue": tickets_pvalue}})
于 2012-11-20T17:02:53.417 回答