6

我想在 haskell 中编写一个无点函数,为了简单起见,可以说我想做这个函数:

maxmin :: Ord a => a -> a -> a -> a
maxmin a b c = max a (min b c)

我可以将其改进为

maxmin a b = (max a) . (min b)

但是有没有办法摆脱a和b?

4

2 回答 2

9

我不会说这更简单,但你去:

maxmin :: Ord a => a -> a -> a -> a                                             
maxmin = (. min) . (.) . max 

pl(使用来自lambdabot http://www.haskell.org/haskellwiki/Pointfree的工具生成)

lambdabot> pl maxmin a b c = max a (min b c)
maxmin = (. min) . (.) . max
于 2012-11-20T14:26:53.407 回答
3

为此,您只需使用“三段定律”

(a `op` b) = (a `op`) b = (`op` b) a = op a b

以便

import Control.Arrow

maxmin a b = (max a) . (min b)
           = (.) (max a) (min b)
           = uncurry (.) (max a, min b)
           = uncurry (.) . (max *** min) $ (a, b)
           = curry (uncurry (.) . (max *** min)) a b

这也不太可读。:)

于 2012-11-20T16:05:08.103 回答