要求;
我必须发送独特的组作为高层的响应。
唯一性条件：
如果两个
<partyfund>组进入一个<request>组，并且每个<partyfund>组具有相同的元素和子组，则删除重复的<partyfund>组。如果一个
<fund>组中有多个<partyfund>组，并且每个<fund>组具有相同的元素和子组，则删除重复<fund>组。如果一个
<fundcollection>组中有多个<fund>组，并且每个<fundcollection>组具有相同的元素和子组，则删除重复<fundcollection>组。如果一个
<valuewithcode>组中有多个<fundcollection>组，并且每个<valuewithcode>组具有相同的元素，则删除重复的组。组内
<fundcollection>假设如果<valuewithcode>出现 2 次，<valuecodeA>并且组<valuecodeB>之间<valuecodeC>的任何一个有差异，<valuewithcode>那么两者都<valuewithcode>应该作为输出发送。为了唯一性，请确保它
<partyfundcode>及其关联组应该是唯一的。
<fundclass>并且<funddate>其关联组<fund>应该是唯一的。
<fundcode>并且它的关联组<fundcollection>应该是唯一的
<valuecodeA> <valuecodeB> <valuecodeC>并且它的关联组<valuewithcode>应该是唯一的
应计算重复节点的数量。
我试图解释这个要求。我也在示例 xml 上尝试了下面的代码并得到了结果，但它没有在
<fund>级别上对元素进行分组。请帮助解决这个问题。
输入 XML：
<request>
<party>
<partyfund>
<partyfundcode>PFC</partyfundcode>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
</fund>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
</fund>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>44444</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
</fund>
</partyfund>
</party>
</request>
我的代码的实际输出
<request>
<partyfund>
<partyfundcode>PFC</partyfundcode>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>40</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>44444</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
</fund>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
</fund>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
</fund>
</partyfund>
</request>
预期结果应该是
<request>
<partyfund>
<partyfundcode>PFC</partyfundcode>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>40</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
</fund>
<fund>
<fundclass>1</fundclass>
<funddate>2001-01-01</funddate>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>10</amount>
<valuecodeA>44444</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
<fundcollection>
<fundcode>CFL</fundcode>
<valuewithcode>
<amount>20</amount>
<valuecodeA>200012DS</valuecodeA>
<valuecodeB>200011GH</valuecodeB>
<valuecodeC>200014UT</valuecodeC>
</valuewithcode>
</fundcollection>
</fund>
</partyfund>
</request>
用于转换的代码
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="partyfund-check" match="partyfund" use="concat(partyfundcode,'+',fund)"/>
<xsl:key name="fund-check" match="fund" use="concat(../partyfundcode,'+',funddate,'+',fundclass)"/>
<xsl:key name="fundcollection-check" match="fundcollection" use="concat(../../partyfundcode,'+',../funddate,'+',../fundclass,'+',fundcode)"/>
<xsl:key name="fundcollection-check1" match="fundcollection" use="concat(../../partyfundcode,'+',../funddate,'+',../fundclass,'+',fundcode,'+',.)"/>
<xsl:key name="valuewithcode-check" match="valuewithcode" use="concat(../../../partyfundcode,'+',../../funddate,'+',../../fundclass,'+',../fundcode,'+',valuecodeA, '+', valuecodeB,'+',valuecodeC,'+',../../fundcollection)"/>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="party">
<xsl:for-each select="partyfund[generate-id(.)=generate-id(key('partyfund-check',concat(partyfundcode,'+',fund))[1])]">
<xsl:for-each select="key('partyfund-check',concat(partyfundcode,'+',fund))">
<partyfund>
<xsl:copy-of select="partyfundcode"/>
<xsl:for-each select="fund[generate-id(.)=generate-id(key('fund-check',concat(../partyfundcode,'+',funddate,'+',fundclass))[1])]">
<xsl:for-each select="key('fund-check',concat(../partyfundcode,'+',funddate,'+',fundclass))">
<fund>
<xsl:copy-of select="fundclass"/>
<xsl:copy-of select="funddate"/>
<xsl:for-each select="fundcollection[generate-id(.)=generate-id(key('fundcollection-check',concat(../../partyfundcode,'+',../funddate,'+',../fundclass,'+',fundcode))[1])]">
<xsl:for-each select="key('fundcollection-check',concat(../../partyfundcode,'+',../funddate,'+',../fundclass,'+',fundcode))[generate-id(.)=generate-id(key('fundcollection-check1',concat(../../partyfundcode,'+',../funddate,'+',../fundclass,'+',fundcode,'+',.))[1])]">
<fundcollection>
<xsl:copy-of select="fundcode"/>
<xsl:for-each select="valuewithcode[generate-id(.)=generate-id(key('valuewithcode-check',concat(../../../partyfundcode,'+',../../funddate,'+',../../fundclass,'+',../fundcode,'+',valuecodeA, '+', valuecodeB,'+',valuecodeC,'+',../../fundcollection))[1])]">
<xsl:for-each select="key('valuewithcode-check',concat(../../../partyfundcode,'+',../../funddate,'+',../../fundclass,'+',../fundcode,'+',valuecodeA, '+', valuecodeB,'+',valuecodeC,'+',../../fundcollection))[1]">
<valuewithcode>
<amount>
<xsl:value-of select="sum(key('valuewithcode-check',concat(../../../partyfundcode,'+',../../funddate,'+',../../fundclass,'+',../fundcode,'+',valuecodeA, '+', valuecodeB,'+',valuecodeC,'+',../../fundcollection))/amount)"/>
</amount>
<xsl:copy-of select="valuecodeA"/>
<xsl:copy-of select="valuecodeB"/>
<xsl:copy-of select="valuecodeC"/>
</valuewithcode>
</xsl:for-each>
</xsl:for-each>
</fundcollection>
</xsl:for-each>
</xsl:for-each>
</fund>
</xsl:for-each>
</xsl:for-each>
</partyfund>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>