退出按钮单击事件。
`void buttn2_Click(object sender, EventArgs e) //QUIT BUTTON CLICK EVENT.
{
if (MessageBox.Show("LEAVE CURRENT GAME?", "QUIT CONFIRMATION", MessageBoxButtons.YesNo) == DialogResult.Yes)
{
this.Controls.Remove(buttn); .. PLAY AGAIN BUTTON.
this.Controls.Remove(buttn2);
for (int i = 0; i <= gencount; i++)
{
this.Controls.Remove(panel[i]);
this.Controls.Remove(label200[i]);
this.Controls.Remove(label100[i]);
this.Controls.Remove(Tbox[i]);
}
this.Controls.Remove(AttemptsRem);
this.Controls.Remove(AttemptNum);
this.Controls.Remove(TimeRem);
this.Controls.Remove(Min);
this.Controls.Remove(Sec);
this.Controls.Remove(misc);
this.ReftoForm2.Show(); To go back to the starting form
}
else
buttn.Focus();
}
Form1 激活事件。
private void Form1_Activated(object sender, EventArgs e)
{
if (ui_formCowsAndBulls.rdbSinglePlayer.Checked == true)//Static variable
{
//GetAllTheWords(); .. Am still working on getting a the 4 letter words
//GetDistinctElements(); .. randomly out of a list.
textBox1.PasswordChar = '*';
textBox1.Focus();
foreach (string val in distinctWords)
{
if (val == "ABLE") .. For single player,the guess word is ABLE.
textBox1.Text = val;
}
}
else
{
textBox1.Text = string.Empty;
textBox1.Enabled = true;
textBox1.Focus();
}
//textBox1.Focus();
}
再次播放点击事件
private void buttn_Click(object sender, EventArgs e) //PLAY AGAIN CLICK EVENT.
{
for (int i = 0; i <= gencount; i++)
{
this.Controls.Remove(panel[i]);
this.Controls.Remove(label200[i]);
this.Controls.Remove(label100[i]);
this.Controls.Remove(Tbox[i]);
}
this.Controls.Remove(AttemptsRem);
this.Controls.Remove(AttemptNum);
textBox1.Text = string.Empty;
textBox1.Enabled = true;
textBox1.Focus();
incrpanel = 0; gencount = 0; count = 10;
this.Controls.Remove(TimeRem);
this.Controls.Remove(Min);
this.Controls.Remove(Sec);
this.Controls.Remove(misc);
this.textBox1.PasswordChar = '*';
this.Controls.Remove(buttn);
this.Controls.Remove(buttn2);
}
我的问题是当我点击消息框按钮NO时我没有从消息框出来。我第一次玩游戏时从消息框出来,但是如果我第二次玩游戏,我需要点击两次才能从消息框出来。如果我第三次玩游戏,我需要单击是或否按钮 3 次才能从消息框出来。我希望你们能帮助我。我发布了同样的问题之前但没有代码。希望代码有所帮助。