-1

这是我之前提出的问题的扩展 - XSLT 1.0 Grouping with multiple elements with same name 输出格式已更改，因此重新发布。

我有一个看起来像的 XML -

<resultset>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning1</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A~level2A~level3A</Hierarchy>
                <Hierarchy>level1B~level2B~level3B</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning2</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A~level2A~level3B</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning3</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A~level2B~level3C</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning4</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A~level2B~level3B</Hierarchy>
                <Hierarchy>level1A~level2B~level3C</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning5</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1B~level2B~level3B</Hierarchy>
            </ITEM>
        </content>
    </hit>
</resultset>

请注意，有多个层次结构元素是 level1~level2~level3 的串联字符串，我希望将其转换为类似这样的内容 -

<TREE>
<LEVELS>
<LEVEL1 name="level1A">
 <LEVEL2 name="level2A">
   <LEVEL3 name="level3A">
      <ITEM Name="Office Cleaning1"/>
   </LEVEL3>
   <LEVEL3 name="level3B">
      <ITEM Name="Office Cleaning2"/>
   </LEVEL3>
 </LEVEL2>
 <LEVEL2 name="level2B">
   <LEVEL3 name="level3B">
        <ITEM Name="Office Cleaning4"/>
   </LEVEL3>
   <LEVEL3 name="level3C">
      <ITEM Name="Office Cleaning3"/>
      <ITEM Name="Office Cleaning4"/>
   </LEVEL3>
 </LEVEL2>
</LEVEL1>
<LEVEL1 name="level1B">
  <LEVEL2 name="level2B">
    <LEVEL3 name="level3B">
        <ITEM Name="Office Cleaning1"/>
        <ITEM Name="Office Cleaning5"/>
    </LEVEL3>
  </LEVEL2>
</LEVEL1>
</TREE>

基本上，每个项目都有多个与之关联的层次结构。我需要将它们组合在一起，并且每个级别也需要组合在一起。

实际上，我可以将输入 XML 中 HIERARCHY 元素中的值更改为任何可能更容易提取的格式。例如，我可以让它看起来像 LEVEL1:level1A~LEVEL2:level2A~LEVEL3:level3A 但我不能添加新元素。

4

1 回答 1

0

I got it working myself. Ignore the extra namespaces. I edited the hierarchy field to have format of level1:value~level2:value~level3:value for ease of substring.

I am sure there is a better way but this works for me.

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:autn="http://schemas.autonomy.com/aci/">
<xsl:output method="xml" omit-xml-declaration="yes"/>

 <xsl:strip-space elements="*"/>

  <xsl:key name="TOPLEVEL" match="autnresponse/responsedata/autn:hit/autn:content/DOCUMENT/HIERARCHY" use="substring-before(substring-after(.,'LEVEL1:'),'~')"/>
  <xsl:key name="MIDLEVEL" match="autnresponse/responsedata/autn:hit/autn:content/DOCUMENT/HIERARCHY" use="substring-before(substring-after(.,'LEVEL2:'),'~')"/>
  <xsl:key name="BOTTOMLEVEL" match="autnresponse/responsedata/autn:hit/autn:content/DOCUMENT/HIERARCHY" use="substring-before(substring-after(.,'LEVEL3:'),'~')"/>


 <xsl:template match="/">
 <TREE>
    <xsl:for-each select="autnresponse/responsedata/autn:hit/autn:content/DOCUMENT/HIERARCHY[generate-id() = generate-id(key('TOPLEVEL',substring-before(substring-after(.,'LEVEL1:'),'~') )[1])]">
    <xsl:variable name="TOP" select="substring-before(substring-after(.,'LEVEL1:'),'~')"/>
     <LEVEL1>
        <xsl:attribute name="name"><xsl:value-of select="substring-after($TOP,'+')"/></xsl:attribute>
        <xsl:attribute name="id"><xsl:value-of select="substring-before($TOP,'+')"/></xsl:attribute>
            <xsl:for-each select="//autnresponse/responsedata/autn:hit/autn:content/DOCUMENT/HIERARCHY[substring-before(substring-after(.,'LEVEL1:'),'~')=$TOP and generate-id() = generate-id(key('MIDLEVEL',substring-before(substring-after(.,'LEVEL2:'),'~') )[1])]">
            <xsl:variable name="MID" select="substring-before(substring-after(.,'LEVEL2:'),'~')"/>
                <LEVEL2>
                    <xsl:attribute name="name"><xsl:value-of select="substring-after($MID,'+')"/></xsl:attribute>
                    <xsl:attribute name="id"><xsl:value-of select="substring-before($MID,'+')"/></xsl:attribute>
                    <xsl:for-each select="//autnresponse/responsedata/autn:hit/autn:content/DOCUMENT/HIERARCHY[substring-before(substring-after(.,'LEVEL1:'),'~')=$TOP  and substring-before(substring-after(.,'LEVEL2:'),'~')=$MID and generate-id() = generate-id(key('BOTTOMLEVEL',substring-before(substring-after(.,'LEVEL3:'),'~') )[1])]">
                    <xsl:variable name="BOTTOM" select="substring-before(substring-after(.,'LEVEL3:'),'~')"/>
                    <LEVEL3>
                        <xsl:attribute name="name"><xsl:value-of select="substring-after($BOTTOM,'+')"/></xsl:attribute>
                        <xsl:attribute name="id"><xsl:value-of select="substring-before($BOTTOM,'+')"/></xsl:attribute>
                        <xsl:apply-templates select="//HIERARCHY[substring-before(substring-after(.,'LEVEL1:'),'~')=$TOP  and substring-before(substring-after(.,'LEVEL2:'),'~')=$MID and substring-before(substring-after(.,'LEVEL3:'),'~')=$BOTTOM]"/>
                    </LEVEL3>
                    </xsl:for-each>
                </LEVEL2>
            </xsl:for-each>
    </LEVEL1>
    </xsl:for-each>
 </TREE>
 </xsl:template>
  <xsl:template match="HIERARCHY">
    <ITEM>
        <xsl:attribute name="name"><xsl:value-of select="../DRETITLE"/></xsl:attribute>
        <xsl:attribute name="id"><xsl:value-of select="../ID"/></xsl:attribute>
    </ITEM>
  </xsl:template>

</xsl:stylesheet>
于 2012-11-07T14:29:15.197 回答