php - PHP：如何显示在 XML xpath 中定义的子节点？

Question

嗨，我想找到一个带有文本字符串“CAT1”的 xml 节点并显示，但我似乎无法正确处理。有人可以告诉我出了什么问题。

---目录.xml---

<?xml version="1.0" encoding="ISO-8859-1"?>
<Catalog>
    <Category>
        <Name>CAT1</Name>
        <Location>
            <Room> Alpha </Room>
        </Location>  
    </Category>
    <Category>
        <Name>CAT2</Name>
        <Location>
            <Room> Bravo </Room>
        </Location>  
    </Category>
    <Category>
        <Name>CAT3</Name>
        <Location>
            <Room> Charlie </Room>
        </Location>  
    </Category>
    <Category>
        <Name>CAT4</Name>
        <Location>
            <Room> Delta </Room>
        </Location>  
    </Category>
</Catalog>

---arr0.php---

<?php
$catalog = simplexml_load_file("catalog.xml");
$category = $catalog->Category;
$name = $category->Name;
$location = $category->Location;
$room = $location->Room;

for ($i = 0; $i <= 22; $i++)
{
$display = $catalog->xpath("//Category/Name[contains(text("CAT1"),'".$category[$i]->$name."']/parent::");
{
echo $display;
echo $room;
}
}
?>

---

结果是显示节点 [Category][Name] = CAT1, [Location][Room] 下列出的所有详细信息，但显示错误

解析错误：语法错误，第 11 行 /home/a3440614/public_html/arr0.php 中的意外 T_STRING

---

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谢谢