r - 填充缺失值

Question

我有一个这样的数据集

 4  6 18 12  4  5
 2  9  0  3 NA 13
11 NA  6  7  7  9

如何使用 R 填充缺失值？

Answer 1

如果您想用固定值（a作为您的数据集）替换您的 NA：

a[is.na(a)] <- 0 #For instance

如果您想将它们替换为行号和列号的函数值（如您在评论中建议的那样）：

#This will replace them by the sum of their row number and their column number:
a[is.na(a)] <- rowSums(which(is.na(a), arr.ind=TRUE))

#This will replace them by their row number:
a[is.na(a)] <- which(is.na(a), arr.ind=TRUE)[,1]

#And this by their column number:
a[is.na(a)] <- which(is.na(a), arr.ind=TRUE)[,2]