12
 CREATE PROCEDURE Pname(in_Tid IN VARCHAR2,in_IP IN VARCHAR2,outstaticip OUT VARCHAR2,outcount OUT NUMBER)
 AS
 BEGIN
 select STATIC_IP into outstaticip from OP_TTER_MAPPING where TERMINAL_ID = in_Tid;
 if in_IP = outstaticip then
 return 1;
 else
 select COUNT(*) into outcount from OP_TTER_MAPPING where DYNAMIC_IP_LOW <= in_IP AND   DYNAMIC_IP_HIGH >= in_IP AND TERMINAL_ID = in_Tid;
 if outcount = 1 then
 return 1;
 else
 return 0;
  end if;
 end if;
 END;
  1. 是否可以像上面那样在存储过程中使用return?
  2. 如果我们可以使用return,我怎样才能在Executesql("begin Pname(----)END")方法中获得该返回值

编辑

现在我像这样在存储过程中编辑了我的返回值,我做得对吗?

CREATE PROCEDURE P_ValidateTIDIP(in_Tid IN VARCHAR2,in_IP IN VARCHAR2,outstaticip OUT VARCHAR2,outcount OUT NUMBER,outretvalue OUT NUMBER)
AS
BEGIN
select STATIC_IP into outstaticip from OP_TTER_MAPPING where TERMINAL_ID = in_Tid;
if in_IP = outstaticip then
    outretvalue:=1;
else 
    select COUNT(*) into outcount from OP_TTER_MAPPING where DYNAMIC_IP_LOW <= in_IP AND DYNAMIC_IP_HIGH >= in_IP AND TERMINAL_ID = in_Tid;
    if outcount = 1 then 
     outretvalue:=1;
    else
     outretvalue:=0;
   end if;
end if;
END;
4

5 回答 5

17

在存储过程中,您使用OUT参数ONLY返回值。正如您在示例中定义了两个变量:

   outstaticip OUT VARCHAR2, outcount OUT NUMBER

只需将返回值分配给输出参数,即outstaticipoutcount从调用位置返回它们。我的意思是:当您调用存储过程时,您也将传递这两个变量。在存储过程调用之后,变量将填充返回值。

如果您想RETURN value从 PL/SQL 调用中获得返回值,请使用FUNCTION. 请注意,以防万一,您只能返回一个变量作为返回变量。

于 2012-11-05T03:25:39.530 回答
6

使用功能:

CREATE OR REPLACE FUNCTION test_function
RETURN VARCHAR2 IS

BEGIN
  RETURN 'This is being returned from a function';
END test_function;
于 2012-11-05T03:27:14.357 回答
5
-- IN arguments : you get them. You can modify them locally but caller won't see it
-- IN OUT arguments: initialized by caller, already have a value, you can modify them and the caller will see it
-- OUT arguments: they're reinitialized by the procedure, the caller will see the final value.
CREATE PROCEDURE f (p IN NUMBER, x IN OUT NUMBER, y OUT NUMBER)
IS
BEGIN
   x:=x * p;
   y:=4 * p;
END;
/

SET SERVEROUTPUT ON

declare
   foo number := 30;
   bar number := 0;
begin
   f(5,foo,bar);
   dbms_output.put_line(foo || ' ' || bar);
end;
/

-- 可以从变量 x 和 y 中收集过程输出(ans1:= x 和 ans2:=y)将分别为:150 和 20。

-- 答案来自:https ://stackoverflow.com/a/9484228/1661078

于 2015-03-03T18:01:32.243 回答
2

有可能的。

当您在过程中使用 Return 时,控制权将转移到调用该过程的调用程序。这就像循环中的出口。

它不会返回任何值。

于 2016-08-16T09:33:01.200 回答
1
CREATE PROCEDURE pr_emp(dept_id IN NUMBER,vv_ename out varchar2  )
 AS
 v_ename emp%rowtype;
CURSOR c_emp IS
    SELECT ename
    FROM emp where deptno=dept_id;
 BEGIN
     OPEN c;
     loop
        FETCH c_emp INTO v_ename;
        return v_ename; 
        vv_ename := v_ename 
        exit when c_emp%notfound;
     end loop;
     CLOSE c_emp;


 END pr_emp;
于 2013-12-27T09:02:41.187 回答