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使用 JSON Parser 在此处解析时发生错误，
请参见以下代码 

- (void)loadDataSource  {  
    // Request  
    NSString *URLPath = [NSString   stringWithFormat:@"https://ajax.googleapis.com/ajax/services/feed/find?   v=1.0&q=Official%20Google%20Blogs"];      
    NSURL *URL = [NSURL URLWithString:URLPath];  
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:URL];

    [NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {

        NSInteger responseCode = [(NSHTTPURLResponse *)response statusCode];

        if (!error && responseCode == 200) {
            id res = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:nil];
            if (res && [res isKindOfClass:[NSDictionary class]]) {
                self.items = [res objectForKey:@"gallery"];
                [self dataSourceDidLoad];
            } else {
                [self dataSourceDidError];
            }
        } else {
            [self dataSourceDidError];
        }
    }];
}

我放了断点，它从 NSURL Connection 中被跳过。如果上面的代码有任何错误，请考虑

提前致谢

4

1 回答 1

0

您的网址中有空格。确保网址正确。

于 2012-11-02T23:50:50.323 回答