我正在尝试将编号列表功能添加到文本编辑器。RichTextbox 已经提供了SelectionBullet
将选择更改为项目符号列表的属性。但我无法找到类似的属性来生成编号列表。是否有任何标准方法可以在 Richtextbox 上创建编号列表。如果没有,我将不得不自己实现它,所以可以帮助我做到这一点的代码片段会有所帮助,谢谢。
问问题
6753 次
3 回答
4
我知道通常不接受链接作为一个好的答案,但是CodeProject 上的带有搜索行编号、项目符号、打印、搜索支持的 RichTextBox文章可能会对您正在寻找的内容有所帮助。
在本文中,作者将 RichTextBox 控件扩展为可以执行您所要求(以及更多)的操作,并且将代码发布在那里供所有人查看。
于 2012-11-02T16:19:48.803 回答
1
好吧,我实现它如下。
private void btnNumbers_Click(object sender, EventArgs e)
{
string temptext = rtbMain.SelectedText;
int SelectionStart = rtbMain.SelectionStart;
int SelectionLength = rtbMain.SelectionLength;
rtbMain.SelectionStart = rtbMain.GetFirstCharIndexOfCurrentLine();
rtbMain.SelectionLength = 0;
rtbMain.SelectedText = "1. ";
int j = 2;
for( int i = SelectionStart; i < SelectionStart + SelectionLength; i++)
if (rtbMain.Text[i] == '\n')
{
rtbMain.SelectionStart = i + 1;
rtbMain.SelectionLength = 0;
rtbMain.SelectedText = j.ToString() + ". ";
j++;
SelectionLength += 3;
}
}
private void rtbMain_KeyDown(object sender, KeyEventArgs e)
{//this piece of code automatically increments the bulleted list when user //presses Enter key
int tempNum;
if (e.KeyCode == Keys.Enter)
try
{
if (char.IsDigit(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine()]))
{
if (char.IsDigit(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 1]) && rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 2] == '.')
tempNum = int.Parse(rtbMain.Text.Substring(rtbMain.GetFirstCharIndexOfCurrentLine(),2));
else tempNum = int.Parse(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine()].ToString());
if (rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 1] == '.' || (char.IsDigit(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 1]) && rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 2] == '.'))
{
tempNum++;
rtbMain.SelectedText = "\r\n" + tempNum.ToString() + ". ";
e.SuppressKeyPress = true;
}
}
}
catch{}
}
于 2012-11-02T18:35:07.727 回答
0
这是我的答案......它易于阅读和改进。我采用了一种截然不同的方法,但添加了删除选择中的编号列表(如果它已经存在)的功能。请注意,到目前为止,我只对它进行了轻微的测试,它似乎工作得很好……但它可能需要进一步改进。
private void btnOrdered_Click(object sender, EventArgs e)
{
string[] splitSelection = null;
// If selection split selection else split everything
if (this.txtCaptionEditor.SelectionLength > 0)
{
splitSelection = this.txtCaptionEditor.SelectedText.Replace("\r\n", "\n").Split("\n".ToCharArray());
}
else
{
splitSelection = this.txtCaptionEditor.Text.Replace("\r\n", "\n").Split("\n".ToCharArray());
}
bool Exists = false;
for (int i = 0; i < splitSelection.GetLength(0); i++)
{
// If Ordered List Allready exists in selection then remove else add
if (!string.IsNullOrEmpty(splitSelection[i]))
{
if (splitSelection[i].Substring(0, 2) == "1.") { Exists = true; }
}
}
for (int i = 0; i < splitSelection.GetLength(0); i++)
{
int lineCount = (i + 1);
if (Exists)
{
this.txtCaptionEditor.Text = this.txtCaptionEditor.Text.Replace(Convert.ToString(lineCount) + ". ", "");
}
else
{
if(!string.IsNullOrEmpty(splitSelection[i]))
{
this.txtCaptionEditor.Text = this.txtCaptionEditor.Text.Replace(splitSelection[i], Convert.ToString(lineCount) + ". " + splitSelection[i]);
}
}
}
}
private void txtCaptionEditor_KeyDown(object sender, KeyEventArgs e)
{
string[] splitSelection = this.txtCaptionEditor.Text.Replace("\r\n", "\n").Split("\n".ToCharArray());
if (e.KeyCode == Keys.Enter)
{
// Get Current Line Position
int currentLine = this.txtCaptionEditor.GetLineFromCharIndex(this.txtCaptionEditor.SelectionStart);
// Only Run if the previous line is greater than zero
if ((currentLine) >= 0)
{
// Loop through 100 possible numbers for match you can go higher
// If you think your numbered list could go above 100
for (int i = 0; i < 100; i++)
{
if (splitSelection[(currentLine)].Substring(0, 2) == Convert.ToString((i + 1)) + ".")
{
// If the substring of the current line equals a numbered list value.. enumerate next line
this.txtCaptionEditor.SelectedText = "\n" + (i + 2) + ". ";
e.SuppressKeyPress = true;
}
}
}
}
}
于 2013-09-03T22:54:11.443 回答