2

我有以下数据结构：文章有 m:n 个用户

共有三个表：articles、users和articles_users（链接表）

现在我需要这个查询：给我所有最近写过文章的用户。

不幸的是，此查询返回重复的结果：

SELECT  DISTINCT users.id, 
        users.username, 
        articles.published, 
        articles_users.user_id
FROM    users 
        INNER JOIN articles_users 
            ON users.id = articles_users.user_id
        INNER JOIN articles     
            ON articles.id = articles_users.article_id
ORDER BY articles.published DESC
LIMIT 25;

结果：

id      username        published   user_id
113     silva_mihat     2012-10-30  112
228     paula_tille     2012-10-27  258
228     paula_tille     2012-10-26  258
631     andrea_gurkow   2012-10-24  631
275     hubert_mayer    2012-10-24  275
198     annette_mulger  2012-10-22  198
255     uta_zuffter     2012-10-22  235
and so on ...

有谁知道为什么 DISTINCT 不在这里工作？

4

2 回答 2

1

因为DISTINCT适用于整行（不仅仅是它 users.id本身）。如您所见，返回的所有行都不是唯一的。尝试这样的事情，子查询背后的想法是它获取published每个的最近日期article_id

SELECT  users.id, 
        users.username, 
        articles.published
FROM    users 
        INNER JOIN articles_users 
            ON users.id = articles_users.user_id
        INNER JOIN articles 
            ON articles.id = articles_users.article_id
        INNER JOIN 
        (
            SELECT id, MAX(published) maxDate
            FROM articles
            GROUP BY id
        ) c ON  articles.id = c.ID AND 
                articles.published = c.maxDATE
-- ORDER BY articles.published DESC
-- LIMIT 25
于 2012-10-31T15:09:17.880 回答
1

这应该按作者而不是按文章分组。 

select
  users.id,
  users.username,
  maxPublished
from users
inner join (
  select
    max(articles.published) as maxPublished,
    articles_users.user_id as userID
  from articles
  join articles_users on articles_users.article_id = articles.id
  group by articles_users.user_id
) as p on users.id = userID
order by maxPublished desc
limit 25
;
于 2012-10-31T15:37:37.963 回答