6

可能重复：
将逗号分隔的字符串转换为单独的行

我有来自存储过程的以下输出，并且想知道将值拆分为多行的最佳方法。

reference   name                            subjects       subjectstitle
LL9X81MT    Making and Decorating Pottery   F06,F27,F38       NULL

我需要修剪逗号处的主题字段并将信息复制到三行，以便数据如下所示。

reference   name                            subjects       subjectstitle
LL9X81MT    Making and Decorating Pottery   F06       NULL
LL9X81MT    Making and Decorating Pottery   F27       NULL
LL9X81MT    Making and Decorating Pottery   F38       NULL

我正在使用 MS SQL Server 2008 来设置这些 SP，只需要一些关于如何拆分主题字段的帮助。

谢谢，

4

2 回答 2

15

您将需要使用类似于此的某种表值拆分函数：

create FUNCTION [dbo].[Split](@String varchar(MAX), @Delimiter char(1))       
returns @temptable TABLE (items varchar(MAX))       
as       
begin      
    declare @idx int       
    declare @slice varchar(8000)       

    select @idx = 1       
        if len(@String)<1 or @String is null  return       

    while @idx!= 0       
    begin       
        set @idx = charindex(@Delimiter,@String)       
        if @idx!=0       
            set @slice = left(@String,@idx - 1)       
        else       
            set @slice = @String       

        if(len(@slice)>0)  
            insert into @temptable(Items) values(@slice)       

        set @String = right(@String,len(@String) - @idx)       
        if len(@String) = 0 break       
    end   
return 
end;

然后，您可以使用outer apply加入 yourtable：

select t1.reference,
  t1.name,
  t1.subjectstitle,
  i.items subjects
from yourtable t1
outer apply dbo.split(t1.subjects, ',') i

给出这样的结果：

| REFERENCE |                          NAME | SUBJECTSTITLE | SUBJECTS |
------------------------------------------------------------------------
|  LL9X81MT | Making and Decorating Pottery |        (null) |      F06 |
|  LL9X81MT | Making and Decorating Pottery |        (null) |      F27 |
|  LL9X81MT | Making and Decorating Pottery |        (null) |      F38 |

参见SQL fiddle with Demo

如果您想在没有拆分功能的情况下执行此操作，则可以使用 CTE：

;with cte (reference, name, subjectstitle, subjectitem, subjects) as
(
  select reference,
    name,
    subjectstitle,
    cast(left(subjects, charindex(',',subjects+',')-1) as varchar(50)) subjectitem,
         stuff(subjects, 1, charindex(',',subjects+','), '') subjects
  from yourtable
  union all
  select reference,
    name,
    subjectstitle,
    cast(left(subjects, charindex(',',subjects+',')-1) as varchar(50)) ,
    stuff(subjects, 1, charindex(',',subjects+','), '') subjects
  from cte
  where subjects > ''
) 
select reference, name, subjectstitle, subjectitem
from cte

请参阅带有演示的 SQL Fiddle

于 2012-10-31T13:55:49.820 回答
11

这将在没有拆分功能的情况下完成

SELECT T1.reference, T1.name, T2.my_Splits AS subjects, T1.subtitile
FROM
 (
  SELECT *,
  CAST('<X>'+replace(T.subjects,',','</X><X>')+'</X>' as XML) as my_Xml 
  FROM [yourTable] T
 ) T1
 CROSS APPLY
 ( 
 SELECT my_Data.D.value('.','varchar(50)') as my_Splits
 FROM T1.my_Xml.nodes('X') as my_Data(D)
 ) T2
于 2012-10-31T15:30:04.273 回答