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我在“module.php”脚本下面有这段代码,它在每个 ModuleId 和 Module Name 的下拉菜单中显示选项:

 $sql = "
    SELECT cm.CourseId, cm.ModuleId, 
    c.CourseName,
    m.ModuleName
    FROM Course c
    INNER JOIN Course_Module cm ON c.CourseId = cm.CourseId
    JOIN Module m ON cm.ModuleId = m.ModuleId
    WHERE
    (c.CourseId = ?)
    ORDER BY c.CourseId, m.ModuleId
    "; 

     $sqlstmt=$mysqli->prepare($sql);

     $sqlstmt->bind_param("s",$course);

     $sqlstmt->execute(); 

     $sqlstmt->bind_result($dbCourseId,$dbModuleId,$dbCourseName,$dbModuleName);


    $moduleHTML  = "";  

     while($sqlstmt->fetch()) { 
        $moduleHTML .= "<option value='$dbModuleId'>" . $dbModuleId . " - " . $dbModuleName . "</option>".PHP_EOL;   
    } 


    echo $moduleHTML; 

     $sqlstmt->execute();

现在我想在单独的页面 (editsession.php) 上回显 ModuleId 和 Module Name,现在我已经设法回显 Module Id 但我的问题是如何在另一个页面上回显模块名称?

    $moduleHTML = "";  
    $moduleHTML .= '<select name="modules" id="modulesDrop">'.PHP_EOL; 
    $moduleHTML .= '<option value="">Please Select</option>'.PHP_EOL;  
    $moduleHTML .= '</select>'; 

if (isset($_POST['moduleSubmit'])) {    

$outputmodule = ""; 
$outputmodule = "<p><strong>Module:</strong> " . $_POST['modules'] .  " - "  . "" . "</p>"; 
4

1 回答 1

0

根据您的 ModuleID 进行 SELECT 查询。

于 2012-10-31T13:30:08.050 回答