0

我有一个非常简单的 python 网络服务器，它返回一些网页，并且不断抛出TypeError: 'str' does not support the buffer interface. 这是我的代码，谁能告诉我哪里错了？

from os import curdir
from os.path import join as pjoin
from http.server import BaseHTTPRequestHandler, HTTPServer
class StoreHandler(BaseHTTPRequestHandler):
    def do_GET(self):
        if self.path == "/store.json":
            with open(pjoin(curdir, 'store.json')) as fh:
                self.send_response(200)
                self.send_header('Content-type','text/json')
                self.end_headers()
                self.wfile.write(fh.read())
        elif self.path == "/Stock.htm":
            with open(pjoin(curdir, 'stock.htm')) as fh:
                self.send_response(200)
                self.send_header('Content-type','text/html')
                self.end_headers()
                self.wfile.write(fh.read())
        else:
            with open(pjoin(curdir, 'index.htm')) as fh:
                self.send_response(200)
                self.send_header('Content-type','text/html')
                self.end_headers()
                self.wfile.write(fh.read())
    def do_POST(self):
        if self.path == '/store.json':
            length = self.headers.getheader('content-length')
            data = self.rfile.read(int(length))
            with open(pjoin(curdir, 'store.json'), 'w') as fh:
                fh.write(data)
            self.send_response(200)

server = HTTPServer(('', 8080), StoreHandler)
server.serve_forever()

这是异常输出：

127.0.0.1 - - [30/Oct/2012 16:48:17] "GET / HTTP/1.1" 200 -
----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 58645)
Traceback (most recent call last):
  File "C:\Program Files\Python33\lib\socketserver.py", line 306, in _handle_request_noblock
    self.process_request(request, client_address)
  File "C:\Program Files\Python33\lib\socketserver.py", line 332, in process_request
    self.finish_request(request, client_address)
  File "C:\Program Files\Python33\lib\socketserver.py", line 345, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "C:\Program Files\Python33\lib\socketserver.py", line 666, in __init__
    self.handle()
  File "C:\Program Files\Python33\lib\http\server.py", line 400, in handle
    self.handle_one_request()
  File "C:\Program Files\Python33\lib\http\server.py", line 388, in handle_one_request
    method()
  File "C:\Users\Arlen\Desktop\Stock Recorder\webserver.py", line 25, in do_GET
    self.wfile.write(fh.read())
  File "C:\Program Files\Python33\lib\socket.py", line 317, in write
    return self._sock.send(b)
TypeError: 'str' does not support the buffer interface
----------------------------------------

更新：这是我更新后的代码的样子：

from os import curdir
from os.path import join as pjoin

from http.server import BaseHTTPRequestHandler, HTTPServer

class StoreHandler(BaseHTTPRequestHandler):
    def do_GET(self):
        if self.path == "/store.json":
            with open(pjoin(curdir, 'store.json')) as fh:
                self.send_response(200)
                self.send_header('Content-type','text/json')
                self.end_headers()
                self.wfile.write(fh.read(), 'rb')
        elif self.path == "/Stock.htm":
            with open(pjoin(curdir, 'stock.htm')) as fh:
                self.send_response(200)
                self.send_header('Content-type','text/html')
                self.end_headers()
                self.wfile.write(fh.read(), 'rb')
        else:
            with open(pjoin(curdir, 'index.htm')) as fh:
                self.send_response(200)
                self.send_header('Content-type','text/html')
                self.end_headers()
                self.wfile.write(fh.read(),'rb')
    def do_POST(self):
        if self.path == '/store.json':
            length = self.headers.getheader('content-length')
            data = self.rfile.read(int(length))
            with open(pjoin(curdir, 'store.json'), 'w') as fh:
                fh.write(data)
            self.send_response(200)

server = HTTPServer(('', 8080), StoreHandler)
server.serve_forever()
4

1 回答 1

0

套接字发送和接收字节，但您尝试通过 unicode 字符串发送，因为您在未指定模式的情况下打开文件（请记住，在 Python 3 中，默认情况下所有字符串都是 unicode）。

您可以：

- 或者 -

  • 以二进制模式打开文件 - 更改open(pjoin(curdir, 'a.file'))为open(pjoin(curdir, 'store.json'), 'rb')（注意附加rb参数）。
于 2012-10-30T21:03:01.053 回答