11

我有一个这样的数据框:

x=c("01","01","01","22","22","03","03","03","35","35")
y=c("f","f","f","m","m","m","m","m","f","f")
df=data.frame(spn=x, sex=y)

看起来像:

   spn sex
1   01   f
2   01   f
3   01   f
4   22   m
5   22   m
6   03   m
7   03   m
8   03   m
9   35   f
10  35   f

我想做的是对 df$spn 进行排序并让它只出现一次。适当的 df$sex 也是如此,例如:

   spn sex
1  01   f
2  03   m
3  22   m
4  35   f

我怎么能那样做?非常感谢!

4

3 回答 3

9
df <- df[order(df$spn), ]
> df[!duplicated(df), ]
  spn sex
1  01   f
6  03   m
4  22   m
9  35   f
于 2012-10-29T21:08:15.247 回答
9
df2 = df[!duplicated(df), ] # Remove duplicated rows.
df3 = df2[order(df2$spn), ] # Sort by the spn column.

df3
#  spn sex
#1  01   f
#6  03   m
#4  22   m
#9  35   f
于 2012-10-29T21:09:02.307 回答
4

使用唯一的然后订购:

df <- unique(df)
df[order(df$spn), ]

使用dplyrdata.table

library(dplyr)
unique(df) %>% arrange(spn)
#   spn sex
# 1  01   f
# 2  03   m
# 3  22   m
# 4  35   f

library(data.table)
unique(setDT(df))[ order(spn), ]
#    spn sex
# 1:  01   f
# 2:  03   m
# 3:  22   m
# 4:  35   f
于 2016-04-08T12:04:46.360 回答