iphone - 字符串 2012-11-09T00:00:00 到 iPhone 中的短日期形式

Question

我有一个字符串格式的日期

2012-11-09T00:00:00

我需要将它作为day=Fri Date-09.

我尝试了很多方法但是日期打印为空。有人可以帮我吗？我想在我创建的自定义日历中显示它。

Answer 1

使用以下代码获取所需的值

NSString *dateStr = @"2012-11-09T00:00:00";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"GMT"]];
[dateFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss"];
NSDate *date = [dateFormatter dateFromString: dateStr];

NSLog(@"Date : %@", date);

NSCalendar *calendar = [NSCalendar currentCalendar];

NSDateComponents *dateComponents =
[calendar components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:date];

NSInteger weekday = [dateComponents weekday];
NSInteger monthdate = [dateComponents day];

NSLog(@"Weekday : %d Month date %d  ", weekday, monthdate);

我们将工作日获取为从 1 到 7 的整数。您必须相应地转换工作日。

Answer 2

试试这个代码：

NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];  
        [dateFormatter setDateFormat:@"dd"];
        NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
        NSDateComponents *comps = [gregorian components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
        int weekday = [comps weekday];
        NSArray *arr=[NSArray arrayWithObjects:@"sun",@"mon",@"tue",@"wed",@"thu",@"fri",@"sat", nil];
        NSLog(@"day=%@ Date-%@",[arr objectAtIndex:weekday-1],[dateFormatter stringFromDate:[NSDate date]]);

当前日期的结果

day=mon Date-29

Answer 3

试试这个方法...

-(NSString *)convertStringToDate:(NSString *) strdate {



    NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
    [dateFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss"];

    NSDate *date = [dateFormatter dateFromString: strdate];

    dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
    [dateFormatter setDateFormat:@"EEE, dd MM yyyy HH:mm:ss"];

    NSString *convertedString = [dateFormatter stringFromDate:date];
    NSLog(@"Converted String : %@",convertedString);
    return convertedString;
}